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Write an equation in slope-intercept form for the line with slope 2 and [tex]y[/tex]-intercept -1.

Sagot :

To write the equation of a line in slope-intercept form, we start with the general formula:
[tex]\[ y = mx + b \][/tex]

In this formula:
- [tex]\( m \)[/tex] is the slope of the line.
- [tex]\( b \)[/tex] is the y-intercept, which is the point where the line crosses the y-axis.

According to the given information:
- The slope ([tex]\( m \)[/tex]) is 2.
- The y-intercept ([tex]\( b \)[/tex]) is -1.

Substitute these values into the slope-intercept form equation:

[tex]\[ y = mx + b \][/tex]
[tex]\[ y = 2x + (-1) \][/tex]

Simplify the equation:

[tex]\[ y = 2x - 1 \][/tex]

Therefore, the equation of the line with a slope of 2 and y-intercept of -1 is:
[tex]\[ y = 2x - 1 \][/tex]