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For the function [tex]f(x) = 2x^2 - 3x + 1[/tex], find the value of [tex]f(-3)[/tex].

Sagot :

GinnyAnswer
Sure! Let's find the value of [tex]\( f(-3) \)[/tex] for the function [tex]\( f(x) = 2x^2 - 3x + 1 \)[/tex].

1. Substitute [tex]\( x = -3 \)[/tex] into the function:

[tex]\[ f(-3) = 2(-3)^2 - 3(-3) + 1 \][/tex]

2. Calculate [tex]\( (-3)^2 \)[/tex]:

[tex]\[ (-3)^2 = 9 \][/tex]

3. Multiply by 2:

[tex]\[ 2 \times 9 = 18 \][/tex]

4. Calculate [tex]\( -3 \times (-3) \)[/tex]:

[tex]\[ -3 \times (-3) = 9 \][/tex]

5. Add all the terms together:

[tex]\[ 18 + 9 + 1 = 28 \][/tex]

So, the value of [tex]\( f(-3) \)[/tex] is [tex]\( 28 \)[/tex].
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