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Sagot :
To solve the problem of subtracting 9 hours from 3 o'clock on a 12-hour clock, let's follow these steps:
1. Identify the initial time:
The initial time given is 3 o'clock.
2. Identify the time to subtract:
We need to subtract 9 hours from the initial time.
3. Perform the subtraction:
Subtract 9 from 3:
[tex]\[ 3 - 9 = -6 \][/tex]
4. Adjust the result using the 12-hour clock cycle:
On a 12-hour clock, any negative result needs to be adjusted back into the range of 1 to 12. To do this, we add 12 (the total number of hours on the clock) to the negative result:
[tex]\[ -6 + 12 = 6 \][/tex]
So, 3 o'clock minus 9 hours on a 12-hour clock results in 6 o'clock.
Therefore, the final answer is:
[tex]\[ 3 - 9 = 6 \][/tex]
1. Identify the initial time:
The initial time given is 3 o'clock.
2. Identify the time to subtract:
We need to subtract 9 hours from the initial time.
3. Perform the subtraction:
Subtract 9 from 3:
[tex]\[ 3 - 9 = -6 \][/tex]
4. Adjust the result using the 12-hour clock cycle:
On a 12-hour clock, any negative result needs to be adjusted back into the range of 1 to 12. To do this, we add 12 (the total number of hours on the clock) to the negative result:
[tex]\[ -6 + 12 = 6 \][/tex]
So, 3 o'clock minus 9 hours on a 12-hour clock results in 6 o'clock.
Therefore, the final answer is:
[tex]\[ 3 - 9 = 6 \][/tex]
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