Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
To solve the problem of subtracting 9 hours from 3 o'clock on a 12-hour clock, let's follow these steps:
1. Identify the initial time:
The initial time given is 3 o'clock.
2. Identify the time to subtract:
We need to subtract 9 hours from the initial time.
3. Perform the subtraction:
Subtract 9 from 3:
[tex]\[ 3 - 9 = -6 \][/tex]
4. Adjust the result using the 12-hour clock cycle:
On a 12-hour clock, any negative result needs to be adjusted back into the range of 1 to 12. To do this, we add 12 (the total number of hours on the clock) to the negative result:
[tex]\[ -6 + 12 = 6 \][/tex]
So, 3 o'clock minus 9 hours on a 12-hour clock results in 6 o'clock.
Therefore, the final answer is:
[tex]\[ 3 - 9 = 6 \][/tex]
1. Identify the initial time:
The initial time given is 3 o'clock.
2. Identify the time to subtract:
We need to subtract 9 hours from the initial time.
3. Perform the subtraction:
Subtract 9 from 3:
[tex]\[ 3 - 9 = -6 \][/tex]
4. Adjust the result using the 12-hour clock cycle:
On a 12-hour clock, any negative result needs to be adjusted back into the range of 1 to 12. To do this, we add 12 (the total number of hours on the clock) to the negative result:
[tex]\[ -6 + 12 = 6 \][/tex]
So, 3 o'clock minus 9 hours on a 12-hour clock results in 6 o'clock.
Therefore, the final answer is:
[tex]\[ 3 - 9 = 6 \][/tex]
We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.