Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
To calculate the magnitude of the electrical force acting between two charges, we use Coulomb's Law. Coulomb's Law states that the magnitude of the force [tex]\( F \)[/tex] between two point charges is given by the formula:
[tex]\[ F = k \cdot \frac{|q_1 \cdot q_2|}{r^2} \][/tex]
where:
- [tex]\( k \)[/tex] is Coulomb's constant ([tex]\( 8.9875517873681764 \times 10^9 \, \text{N} \cdot \text{m}^2 / \text{C}^2 \)[/tex]),
- [tex]\( q_1 \)[/tex] and [tex]\( q_2 \)[/tex] are the magnitudes of the charges,
- [tex]\( r \)[/tex] is the distance between the charges.
Given:
- [tex]\( q_1 = 2.4 \times 10^{-8} \, \text{C} \)[/tex]
- [tex]\( q_2 = 1.8 \times 10^{-6} \, \text{C} \)[/tex]
- [tex]\( r = 0.008 \, \text{m} \)[/tex]
Step-by-step solution:
1. Calculate the product of the charges:
[tex]\[ |q_1 \times q_2| = (2.4 \times 10^{-8} \, \text{C}) \times (1.8 \times 10^{-6} \, \text{C}) \][/tex]
[tex]\[ = 4.32 \times 10^{-14} \, \text{C}^2 \][/tex]
2. Square the distance:
[tex]\[ r^2 = (0.008 \, \text{m})^2 \][/tex]
[tex]\[ = 6.4 \times 10^{-5} \, \text{m}^2 \][/tex]
3. Apply Coulomb's Law formula:
[tex]\[ F = \frac{8.9875517873681764 \times 10^9 \, \text{N} \cdot \text{m}^2 / \text{C}^2 \times 4.32 \times 10^{-14} \, \text{C}^2}{6.4 \times 10^{-5} \, \text{m}^2} \][/tex]
[tex]\[ = 6.0665974564735174 \, \text{N} \][/tex]
4. Round the result to the tenths place:
[tex]\[ F \approx 6.1 \, \text{N} \][/tex]
Therefore, the magnitude of the electrical force acting between the charges is [tex]\( 6.1 \, \text{N} \)[/tex], rounded to the tenths place.
[tex]\[ F = k \cdot \frac{|q_1 \cdot q_2|}{r^2} \][/tex]
where:
- [tex]\( k \)[/tex] is Coulomb's constant ([tex]\( 8.9875517873681764 \times 10^9 \, \text{N} \cdot \text{m}^2 / \text{C}^2 \)[/tex]),
- [tex]\( q_1 \)[/tex] and [tex]\( q_2 \)[/tex] are the magnitudes of the charges,
- [tex]\( r \)[/tex] is the distance between the charges.
Given:
- [tex]\( q_1 = 2.4 \times 10^{-8} \, \text{C} \)[/tex]
- [tex]\( q_2 = 1.8 \times 10^{-6} \, \text{C} \)[/tex]
- [tex]\( r = 0.008 \, \text{m} \)[/tex]
Step-by-step solution:
1. Calculate the product of the charges:
[tex]\[ |q_1 \times q_2| = (2.4 \times 10^{-8} \, \text{C}) \times (1.8 \times 10^{-6} \, \text{C}) \][/tex]
[tex]\[ = 4.32 \times 10^{-14} \, \text{C}^2 \][/tex]
2. Square the distance:
[tex]\[ r^2 = (0.008 \, \text{m})^2 \][/tex]
[tex]\[ = 6.4 \times 10^{-5} \, \text{m}^2 \][/tex]
3. Apply Coulomb's Law formula:
[tex]\[ F = \frac{8.9875517873681764 \times 10^9 \, \text{N} \cdot \text{m}^2 / \text{C}^2 \times 4.32 \times 10^{-14} \, \text{C}^2}{6.4 \times 10^{-5} \, \text{m}^2} \][/tex]
[tex]\[ = 6.0665974564735174 \, \text{N} \][/tex]
4. Round the result to the tenths place:
[tex]\[ F \approx 6.1 \, \text{N} \][/tex]
Therefore, the magnitude of the electrical force acting between the charges is [tex]\( 6.1 \, \text{N} \)[/tex], rounded to the tenths place.
We hope this was helpful. Please come back whenever you need more information or answers to your queries. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.