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Sagot :
To determine the net force acting on the car, we can apply Newton's second law of motion, which states:
[tex]\[ F = m \cdot a \][/tex]
where:
- [tex]\( F \)[/tex] is the net force
- [tex]\( m \)[/tex] is the mass of the object
- [tex]\( a \)[/tex] is the acceleration
Here are the given values:
- The mass [tex]\( m \)[/tex] of the car is [tex]\( 1.00 \times 10^3 \)[/tex] kilograms
- The acceleration [tex]\( a \)[/tex] of the car is [tex]\( 4.5 \)[/tex] meters/second[tex]\(^2\)[/tex]
Let's substitute these values into the formula:
[tex]\[ F = (1.00 \times 10^3\, \text{kg}) \cdot (4.5\, \text{m/s}^2) \][/tex]
Now we carry out the multiplication:
[tex]\[ F = 1.00 \times 10^3 \times 4.5 \][/tex]
[tex]\[ F = 4.5 \times 10^3 \][/tex]
We find that the net force [tex]\( F \)[/tex] is [tex]\( 4.5 \times 10^3 \)[/tex] newtons.
Thus, the correct answer is:
C. [tex]\( 4.5 \times 10^3 \)[/tex] newtons
[tex]\[ F = m \cdot a \][/tex]
where:
- [tex]\( F \)[/tex] is the net force
- [tex]\( m \)[/tex] is the mass of the object
- [tex]\( a \)[/tex] is the acceleration
Here are the given values:
- The mass [tex]\( m \)[/tex] of the car is [tex]\( 1.00 \times 10^3 \)[/tex] kilograms
- The acceleration [tex]\( a \)[/tex] of the car is [tex]\( 4.5 \)[/tex] meters/second[tex]\(^2\)[/tex]
Let's substitute these values into the formula:
[tex]\[ F = (1.00 \times 10^3\, \text{kg}) \cdot (4.5\, \text{m/s}^2) \][/tex]
Now we carry out the multiplication:
[tex]\[ F = 1.00 \times 10^3 \times 4.5 \][/tex]
[tex]\[ F = 4.5 \times 10^3 \][/tex]
We find that the net force [tex]\( F \)[/tex] is [tex]\( 4.5 \times 10^3 \)[/tex] newtons.
Thus, the correct answer is:
C. [tex]\( 4.5 \times 10^3 \)[/tex] newtons
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