Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Get quick and reliable solutions to your questions from a community of experienced professionals on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
To solve for [tex]\(\log_8(25)\)[/tex], Devonte used the Change of Base Formula. The Change of Base Formula is useful when you need to compute logarithms with bases other than 10 or e (the natural logarithm base), which are directly supported by most calculators.
The Change of Base Formula states that for any positive numbers [tex]\(a\)[/tex], [tex]\(b\)[/tex], and [tex]\(c\)[/tex] (where [tex]\(a \neq 1\)[/tex] and [tex]\(b \neq 1\)[/tex]):
[tex]\[ \log_a b = \frac{\log_c b}{\log_c a} \][/tex]
In our specific case, we want to approximate [tex]\(\log_8(25)\)[/tex], so let's apply the formula:
[tex]\[ \log_8(25) = \frac{\log (25)}{\log (8)} \][/tex]
Here, the expression [tex]\(\frac{\log (25)}{\log (8)}\)[/tex] represents the base 8 logarithm of 25 using the common logarithm (base 10).
Thus, Devonte used the following expression to approximate [tex]\(\log_8(25)\)[/tex]:
[tex]\[ \boxed{\frac{\log 25}{\log 8}} \][/tex]
Now, let's verify that this is indeed the correct expression:
Given our earlier calculations, [tex]\(\frac{\log 25}{\log 8} \approx 1.5479520632582415\)[/tex], we can be confident that:
[tex]\[ \log_8(25) \approx 1.5479520632582415 \][/tex]
Therefore, Devonte correctly used the expression:
[tex]\[ \frac{\log 25}{\log 8} \][/tex]
[tex]\[ \boxed{\frac{\log 25}{\log 8}} \][/tex]
The Change of Base Formula states that for any positive numbers [tex]\(a\)[/tex], [tex]\(b\)[/tex], and [tex]\(c\)[/tex] (where [tex]\(a \neq 1\)[/tex] and [tex]\(b \neq 1\)[/tex]):
[tex]\[ \log_a b = \frac{\log_c b}{\log_c a} \][/tex]
In our specific case, we want to approximate [tex]\(\log_8(25)\)[/tex], so let's apply the formula:
[tex]\[ \log_8(25) = \frac{\log (25)}{\log (8)} \][/tex]
Here, the expression [tex]\(\frac{\log (25)}{\log (8)}\)[/tex] represents the base 8 logarithm of 25 using the common logarithm (base 10).
Thus, Devonte used the following expression to approximate [tex]\(\log_8(25)\)[/tex]:
[tex]\[ \boxed{\frac{\log 25}{\log 8}} \][/tex]
Now, let's verify that this is indeed the correct expression:
Given our earlier calculations, [tex]\(\frac{\log 25}{\log 8} \approx 1.5479520632582415\)[/tex], we can be confident that:
[tex]\[ \log_8(25) \approx 1.5479520632582415 \][/tex]
Therefore, Devonte correctly used the expression:
[tex]\[ \frac{\log 25}{\log 8} \][/tex]
[tex]\[ \boxed{\frac{\log 25}{\log 8}} \][/tex]
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.