Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Two fruit flies that are heterozygous for body color and eye color are crossed. Brown body color is dominant to black body color. Red eye color is dominant to brown eye color.

Determine the genotypes of offspring 1-8.

1. [tex]$\square$[/tex]
2. [tex]$\square$[/tex]
3. [tex]$\square$[/tex]
4. [tex]$\square$[/tex]
5. [tex]$\square$[/tex]
6. [tex]$\square$[/tex]
7. [tex]$\square$[/tex]
8. [tex]$\square$[/tex]

Sagot :

When solving this problem, we need to consider the principles of Mendelian genetics and understand how these traits are inherited. Here, we are dealing with two traits: body color and eye color. Each trait has two alleles, one dominant and one recessive.

1. Body Color:
- Brown body color (B) is dominant.
- Black body color (b) is recessive.

2. Eye Color:
- Red eye color (R) is dominant.
- Brown eye color (r) is recessive.

Since the parents are heterozygous for both traits, their genotypes are both BbRr. When two heterozygous individuals are crossed, we can use a Punnett square to determine the possible genotypes of the offspring.

We'll use a 4x4 Punnett square to list all possible combinations of alleles for both traits.

Constructing the Punnett Square:

Parents' genotypes:
[tex]\[BbRr \times BbRr\][/tex]

The gametes they can produce (B can pair with R/r and b can pair with R/r):
[tex]\[BR, Br, bR, br\][/tex]

We will cross each gamete combination using the Punnett square:

[tex]\[ \begin{array}{c|c|c|c|c} & BR & Br & bR & br \\ \hline BR & BBRR & BBRr & BbRR & BbRr \\ \hline Br & BBRr & BBrr & BbRr & Bbrr \\ \hline bR & BbRR & BbRr & bbRR & bbRr \\ \hline br & BbRr & Bbrr & bbRr & bbrr \\ \end{array} \][/tex]

List of all possible genotypes and their counts:
- BBRR, BBRr, BbRR, BbRr, BBrr, Bbrr, bbRR, bbRr, bbrr

Let's number the offspring and list the possible genotypes:

1. BBRR
- Homozygous dominant for both traits

2. BBRr
- Homozygous dominant for body color and heterozygous for eye color

3. BbRR
- Heterozygous for body color and homozygous dominant for eye color

4. BbRr
- Heterozygous for both traits

5. BBrr
- Homozygous dominant for body color and homozygous recessive for eye color

6. Bbrr
- Heterozygous for body color and homozygous recessive for eye color

7. bbRR
- Homozygous recessive for body color and homozygous dominant for eye color

8. bbRr
- Homozygous recessive for body color and heterozygous for eye color

Thus, the possible genotypes for offspring 1-8 would be:
1. BBRR
2. BBRr
3. BbRR
4. BbRr
5. BBrr
6. Bbrr
7. bbRR
8. bbRr
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.