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A part of an mRNA molecule with the following sequence is being read by a ribosome: [tex]$5^{\prime}-C C G-A C G-3^{\prime}$[/tex] (mRNA). The charged transfer RNA molecules shown in the figure (with their anticodons shown in the [tex]$3^{\prime}$[/tex] to [tex]$5^{\prime}$[/tex] direction) are available. Two of them can correctly match the mRNA so that a dipeptide can form.

The dipeptide that will form will be

\begin{tabular}{|c|l|}
\hline tRNA Anticodon & Amino Acid \\
\hline GGC & Proline \\
CGU & Alanine \\
UGC & Threonine \\
CCG & Glycine \\
ACG & Cysteine \\
CGG & Alanine \\
\hline
\end{tabular}

A. threonine-glycine
B. glycine-cysteine
C. cysteine-alanine
D. proline-threonine
E. alanine-alanine

Sagot :

GinnyAnswer
To determine which dipeptide will form, we'll go through the following steps:

1. Understand mRNA Codons:
mRNA codons read in the 5' to 3' direction are:
- [tex]$5'-C C G-3'$[/tex]
- [tex]$5'-A C G-3'$[/tex]

2. Find Complementary tRNA Anticodons:
tRNA anticodons are read in the 3' to 5' direction to match the mRNA codons. Therefore:
- The complementary anticodon for the mRNA codon [tex]$5'-C C G-3'$[/tex] will be [tex]$3'-G G C-5'$[/tex].
- The complementary anticodon for the mRNA codon [tex]$5'-A C G-3'$[/tex] will be [tex]$3'-U G C-5'$[/tex].

3. Match Anticodons with tRNA Chart:
Using the given tRNA anticodon table, we match the anticodons with their corresponding amino acids:
- Anticodon [tex]$3'-G G C-5'$[/tex] corresponds to Proline
- Anticodon [tex]$3'-U G C-5'$[/tex] corresponds to Threonine

4. Determine the Amino Acid Sequence:
The mRNA sequence [tex]$5'-C C G-3'$[/tex] corresponds to Proline, and the mRNA sequence [tex]$5'-A C G-3'$[/tex] corresponds to Threonine.

Therefore, the dipeptide formed by these two mRNA codons will be:

Proline-Threonine

Based on the provided options in the question, the correct answer is:

Proline-Threonine.
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