Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

If an object is dropped from a height of [tex]$h$[/tex] meters and hits the ground in [tex]$t$[/tex] seconds, then [tex]$t=\sqrt{\frac{h}{4.9}}$[/tex].

Suppose that an object is dropped from the top of a building that is 135.73 meters tall. How long does it take to hit the ground?

Round your answer to the nearest tenth.


Sagot :

To determine the time it takes for an object to hit the ground when dropped from a height of [tex]\( h \)[/tex] meters, we can use the given formula:

[tex]\[ t = \sqrt{\frac{h}{4.9}} \][/tex]

In this case, the height [tex]\( h \)[/tex] is given as 135.73 meters. We'll follow these steps to find the time [tex]\( t \)[/tex]:

1. Substitute the given height into the formula:
[tex]\[ t = \sqrt{\frac{135.73}{4.9}} \][/tex]

2. Perform the division inside the square root:
[tex]\[ \frac{135.73}{4.9} \approx 27.700 \][/tex]

3. Now, take the square root of the result:
[tex]\[ t = \sqrt{27.700} \][/tex]

4. Calculating the square root gives us the raw time value:
[tex]\[ t \approx 5.263 \][/tex]

5. Round this value to the nearest tenth:
[tex]\[ t \approx 5.3 \][/tex]

Thus, the object takes approximately [tex]\( 5.3 \)[/tex] seconds to hit the ground when dropped from a height of 135.73 meters.