Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Charlotte joined a book club to spend more quality time with her cousin. At the first meeting, club members recorded how many hours a week they typically read and whether they preferred e-readers or paperback books.

\begin{tabular}{|l|c|c|}
\cline { 2 - 3 } & E-readers & Paperback books \\
\hline About 1 hour per week & 11 & 4 \\
\hline About 3 hours per week & 5 & 12 \\
\hline About 5 hours per week & 6 & 6 \\
\hline
\end{tabular}

What is the probability that a randomly selected club member prefers paperback books and does not read about 1 hour per week?

Simplify any fractions.
[tex]$\square$[/tex]


Sagot :

To determine the probability that a randomly selected club member prefers paperback books and does not read about 1 hour per week, we'll start by analyzing the given data and following a step-by-step approach.

1. Identify the Total Number of Members:
From the given table, we categorize the members based on their reading preferences and weekly reading hours.
- E-readers, About 1 hour per week: 11 members
- Paperback books, About 1 hour per week: 4 members
- E-readers, About 3 hours per week: 5 members
- Paperback books, About 3 hours per week: 12 members
- E-readers, About 5 hours per week: 6 members
- Paperback books, About 5 hours per week: 6 members

To find the total number of club members:
[tex]\[ \text{Total members} = 11 + 4 + 5 + 12 + 6 + 6 = 44 \text{ members} \][/tex]

2. Determine the Number of Members Who Prefer Paperback Books and Do Not Read About 1 Hour per Week:
We are interested in members who prefer paperback books and read for about 3 hours or 5 hours per week.
- Paperback books, About 3 hours per week: 12 members
- Paperback books, About 5 hours per week: 6 members

Therefore, the total number of members who prefer paperback books and do not read about 1 hour per week is:
[tex]\[ \text{Prefer paperback and not 1 hour} = 12 + 6 = 18 \text{ members} \][/tex]

3. Calculate the Probability:
The probability [tex]\( P \)[/tex] of selecting a club member who prefers paperback books and does not read about 1 hour per week is given by the ratio of the number of favorable outcomes to the total number of club members:
[tex]\[ P = \frac{\text{Prefer paperback and not 1 hour}}{\text{Total members}} = \frac{18}{44} \][/tex]

4. Simplify the Fraction:
The fraction [tex]\(\frac{18}{44}\)[/tex] can be simplified by dividing both the numerator and the denominator by their greatest common divisor (GCD), which is 2:
[tex]\[ \frac{18 \div 2}{44 \div 2} = \frac{9}{22} \][/tex]

Thus, the simplified probability that a randomly selected club member prefers paperback books and does not read about 1 hour per week is:
[tex]\[ \boxed{\frac{9}{22}} \][/tex]

In decimal form, this probability is approximately [tex]\(0.409\)[/tex].