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How many atoms of germanium are present in a sample containing 4.20 moles of Ge?

[tex]\[
[?] \times 10^{[?]} \text{ atoms Ge}
\][/tex]


Sagot :

To determine the number of atoms in a sample containing 4.20 moles of Germanium (Ge), we can use Avogadro's number, which is [tex]\( 6.022 \times 10^{23} \)[/tex] atoms per mole.

Here are the steps to find the number of atoms:

1. Identify the number of moles: In the problem, we are given the number of moles of Germanium, which is [tex]\( 4.20 \)[/tex] moles.

2. Use Avogadro's number: Avogadro's number ([tex]\( N_A \)[/tex]) is the number of atoms in one mole of a substance. It is [tex]\( 6.022 \times 10^{23} \)[/tex] atoms/mole.

3. Calculate the total number of atoms:
- Multiply the number of moles of Germanium by Avogadro's number:
[tex]\[ \text{Number of atoms} = \text{Number of moles} \times \text{Avogadro's number} \][/tex]
- Plug in the given values:
[tex]\[ \text{Number of atoms} = 4.20 \, \text{moles} \times 6.022 \times 10^{23} \, \text{atoms/mole} \][/tex]

4. Perform the multiplication:
- Calculate the product:
[tex]\[ \text{Number of atoms} = 2.52924 \times 10^{24} \, \text{atoms} \][/tex]

Therefore, the number of atoms of Germanium in 4.20 moles of Ge is:
[tex]\[ 2.52924 \times 10^{24} \, \text{atoms} \][/tex]