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Van guessed on all 8 questions of a multiple-choice quiz. Each question has 4 answer choices. What is the probability that he got exactly 1 question correct? Round the answer to the nearest thousandth.

[tex]\[
P(k \text{ successes}) = { }_n C_k p^k (1-p)^{n-k} \\
{ }_n C_k = \frac{n!}{(n-k)!\cdot k!}
\][/tex]

A. 0.033
B. 0.267
C. 0.461
D. 0.733


Sagot :

To determine the probability that Van got exactly 1 question correct out of 8, when each question has 4 answer choices, we use the binomial probability formula:
[tex]\[ P(k \text{ successes }) = \binom{n}{k} p^k (1-p)^{n-k} \][/tex]
Here, [tex]\( n \)[/tex] is the number of questions, [tex]\( k \)[/tex] is the number of successes (questions answered correctly), and [tex]\( p \)[/tex] is the probability of success for each question.

Let's break it down step by step:

1. Number of questions [tex]\( n \)[/tex]: 8
2. Number of successful guesses [tex]\( k \)[/tex]: 1
3. Probability of a successful guess [tex]\( p \)[/tex]: [tex]\(\frac{1}{4} = 0.25\)[/tex] (since there are 4 choices per question and only one correct choice).

First, we calculate the binomial coefficient [tex]\(\binom{n}{k}\)[/tex], which represents the number of ways to choose [tex]\( k \)[/tex] successes from [tex]\( n \)[/tex] trials:
[tex]\[ \binom{8}{1} = \frac{8!}{(8-1)!\cdot 1!} = \frac{8!}{7! \cdot 1!} = 8 \][/tex]

Next, we calculate the probability of exactly 1 success [tex]\( p^k \)[/tex]:
[tex]\[ p^k = (0.25)^1 = 0.25 \][/tex]

Then, we calculate the probability of [tex]\( n - k \)[/tex] failures:
[tex]\[ (1-p)^{n-k} = (1-0.25)^{8-1} = 0.75^7 \approx 0.133484 \][/tex]

Now, using these values, we calculate the overall probability using the binomial formula:
[tex]\[ P(1 \text{ success in 8 trials}) = \binom{8}{1} \cdot 0.25 \cdot 0.133484 = 8 \cdot 0.25 \cdot 0.133484 \approx 0.267 \][/tex]

Thus, the probability that Van got exactly 1 question correct, rounding to the nearest thousandth, is:
[tex]\[ \boxed{0.267} \][/tex]