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The area of an equilateral triangle is [tex]$9 \sqrt{3} \, \text{cm}^2$[/tex]. Find its perimeter.

उटा समबाहु त्रिभुजको क्षेत्रफल [tex]$9 \sqrt{3} \, \text{cm}^2$[/tex] छ भने त्यसको परिमिति निकाल्नुहोस्।


Sagot :

To find the perimeter of an equilateral triangle with an area of [tex]\( 9 \sqrt{3} \ \text{cm}^2 \)[/tex], we can follow these steps:

1. Recall the area formula of an equilateral triangle:
[tex]\[ \text{Area} = \frac{\sqrt{3}}{4} a^2 \][/tex]
Here, [tex]\( a \)[/tex] is the side length of the equilateral triangle, and we know the area is [tex]\( 9 \sqrt{3} \ \text{cm}^2 \)[/tex].

2. Set up the equation with the given area:
[tex]\[ 9 \sqrt{3} = \frac{\sqrt{3}}{4} a^2 \][/tex]

3. Solve for [tex]\( a^2 \)[/tex]:
Multiply both sides of the equation by 4:
[tex]\[ 36 \sqrt{3} = \sqrt{3} a^2 \][/tex]

4. Divide both sides by [tex]\( \sqrt{3} \)[/tex]:
[tex]\[ 36 = a^2 \][/tex]

5. Solve for [tex]\( a \)[/tex]:
[tex]\[ a = \sqrt{36} = 6 \ \text{cm} \][/tex]
So, the side length of the equilateral triangle is 6 cm.

6. Find the perimeter of the equilateral triangle:
The perimeter [tex]\( P \)[/tex] is three times the side length [tex]\( a \)[/tex]:
[tex]\[ P = 3 \times a = 3 \times 6 = 18 \ \text{cm} \][/tex]

Therefore, the perimeter of the equilateral triangle is [tex]\( 18 \ \text{cm} \)[/tex].

तसर्थ, समबाहु त्रिभुजको परिमिति [tex]\( 18 \ \text{cm} \)[/tex] छ।