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Which are correct representations of the inequality [tex]6x \geq 3 + 4(2x - 1)[/tex]? Select three options.

A. [tex]1 \geq 2x[/tex]
B. [tex]6x \geq 3 + 8x - 4[/tex]


Sagot :

To determine which are correct representations of the inequality [tex]\(6x \geq 3 + 4(2x - 1)\)[/tex], let's solve the inequality step-by-step.

1. Start with the given inequality:
[tex]\[ 6x \geq 3 + 4(2x - 1) \][/tex]

2. Distribute the 4 on the right side:
[tex]\[ 4(2x - 1) = 4 \cdot 2x - 4 \cdot 1 = 8x - 4 \][/tex]

3. Substitute this back into the inequality:
[tex]\[ 6x \geq 3 + 8x - 4 \][/tex]

4. Combine like terms on the right side:
[tex]\[ 6x \geq 8x - 1 \][/tex]

5. To isolate [tex]\(x\)[/tex], subtract [tex]\(8x\)[/tex] from both sides:
[tex]\[ 6x - 8x \geq -1 \][/tex]
[tex]\[ -2x \geq -1 \][/tex]

6. To solve for [tex]\(x\)[/tex], divide both sides by [tex]\(-2\)[/tex] and remember to reverse the inequality sign when dividing by a negative number:
[tex]\[ x \leq \frac{1}{2} \][/tex]

So, the solution to the inequality is [tex]\(x \leq \frac{1}{2}\)[/tex].

Now, let's verify which representations are correct:

1. [tex]\(1 \geq 2x\)[/tex]

This representation simplifies to:
[tex]\[ \frac{1}{2} \geq x \quad \text{or} \quad x \leq \frac{1}{2} \][/tex]
This is indeed correct and matches our solution.

2. [tex]\(6x \geq 3 + 8x - 4\)[/tex]

Simplifying inside:
[tex]\[ 3 + 8x - 4 = 8x - 1 \][/tex]
Which gives us:
[tex]\[ 6x \geq 8x - 1 \][/tex]
This is also correct and matches our earlier steps.

Thus, the correct representations of the inequality are:
- [tex]\(1 \geq 2x\)[/tex]
- [tex]\(6x \geq 3 + 8x - 4\)[/tex]

We have successfully found the two correct representations of the inequality.
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