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Sagot :
To determine how many hours it will take for the bacterial count to reach 2,048, let's continue the table provided.
From the table:
[tex]\[ \begin{array}{|c|c|} \hline \text{Time (hours), } x & \text{Bacterial Count} \\ \hline 1 & 2^1 = 2 \\ \hline 2 & 2^2 = 4 \\ \hline 3 & 2^3 = 8 \\ \hline 4 & 2^4 = 16 \\ \hline 5 & 2^5 = 32 \\ \hline \end{array} \][/tex]
We need to continue the table until we reach a bacterial count of 2,048:
[tex]\[ \begin{array}{|c|c|} \hline 6 & 2^6 = 64 \\ \hline 7 & 2^7 = 128 \\ \hline 8 & 2^8 = 256 \\ \hline 9 & 2^9 = 512 \\ \hline 10 & 2^{10} = 1024 \\ \hline 11 & 2^{11} = 2048 \\ \hline \end{array} \][/tex]
Therefore, the bacterial count will reach 2,048 after [tex]\( \boxed{11} \)[/tex] hours.
From the table:
[tex]\[ \begin{array}{|c|c|} \hline \text{Time (hours), } x & \text{Bacterial Count} \\ \hline 1 & 2^1 = 2 \\ \hline 2 & 2^2 = 4 \\ \hline 3 & 2^3 = 8 \\ \hline 4 & 2^4 = 16 \\ \hline 5 & 2^5 = 32 \\ \hline \end{array} \][/tex]
We need to continue the table until we reach a bacterial count of 2,048:
[tex]\[ \begin{array}{|c|c|} \hline 6 & 2^6 = 64 \\ \hline 7 & 2^7 = 128 \\ \hline 8 & 2^8 = 256 \\ \hline 9 & 2^9 = 512 \\ \hline 10 & 2^{10} = 1024 \\ \hline 11 & 2^{11} = 2048 \\ \hline \end{array} \][/tex]
Therefore, the bacterial count will reach 2,048 after [tex]\( \boxed{11} \)[/tex] hours.
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