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What are the zeros of [tex]$g(x)=x^3+6x^2-9x-54$[/tex]?

A. [tex]$1, 2, 27$[/tex]

B. [tex][tex]$3, -3, -6$[/tex][/tex]

C. [tex]$-6, 3, 6$[/tex]

D. [tex]$2, -1, 18$[/tex]


Sagot :

To find the zeros of the polynomial function [tex]\( g(x) = x^3 + 6x^2 - 9x - 54 \)[/tex], we need to determine the values of [tex]\( x \)[/tex] such that [tex]\( g(x) = 0 \)[/tex].

Let's follow a step-by-step approach to solving this polynomial equation:

1. Identify the polynomial equation:
The given polynomial equation is:
[tex]\[ g(x) = x^3 + 6x^2 - 9x - 54 \][/tex]

2. Set the polynomial equal to zero:
We need to solve for [tex]\( x \)[/tex] in the equation:
[tex]\[ x^3 + 6x^2 - 9x - 54 = 0 \][/tex]

3. Determine the zeros of the polynomial:
The zeros of a polynomial are the values of [tex]\( x \)[/tex] that satisfy the equation [tex]\( g(x) = 0 \)[/tex].

Through our calculations, we find that the zeros of the polynomial [tex]\( g(x) \)[/tex] are:
[tex]\[ x = -6, -3, 3 \][/tex]

4. Select the correct answer based on the found zeros:
Given the options, the correct answer that includes [tex]\( -6, -3, 3 \)[/tex] is:
[tex]\[ \text{B. } -6, -3, 3 \][/tex]

Therefore, the correct answer to the question "What are the zeros of [tex]\( g(x) = x^3 + 6x^2 - 9x - 54 \)[/tex]?" is:
[tex]\[ \text{B. } -6, -3, 3 \][/tex]