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In physics class, Carre learns that a force, [tex]F[/tex], is equal to the mass of an object, [tex]m[/tex], times its acceleration, [tex]a[/tex]. She writes the equation [tex]F = ma[/tex].

Using this formula, what is the acceleration of an object with [tex]F = 7.92[/tex] newtons and [tex]m = 3.6[/tex] kilograms? Express your answer to the nearest tenth.

Note: The unit for force (the newton) is measured in [tex]\frac{\text{kg} \cdot \text{m}}{\text{s}^2}[/tex].

A. [tex]0.5 \frac{\text{m}}{\text{s}^2}[/tex]
B. [tex]x = \frac{\text{m}}{2}[/tex]
C. [tex]2.2 \frac{\text{m}}{\text{s}^2}[/tex]
D. [tex]4.0 \frac{\text{m}}{2}[/tex]

Sagot :

To find the acceleration of an object using the formula [tex]\( F = ma \)[/tex], we can rearrange the equation to solve for [tex]\( a \)[/tex]. The formula becomes:

[tex]\[ a = \frac{F}{m} \][/tex]

Given:
- The force [tex]\( F \)[/tex] is 7.92 newtons
- The mass [tex]\( m \)[/tex] is 3.6 kilograms

We substitute these values into the equation:

[tex]\[ a = \frac{7.92 \text{ N}}{3.6 \text{ kg}} \][/tex]

Dividing the values, we get the acceleration:

[tex]\[ a = 2.1999999999999997 \text{ m/s}^2 \][/tex]

Now, we need to express this answer to the nearest tenth. The number 2.1999999999999997 rounds to 2.2 when rounded to the nearest tenth.

Therefore, the acceleration of the object is:

[tex]\[ \boxed{2.2 \, \text{m/s}^2} \][/tex]