Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Select the correct answer.

Solve the quadratic equation.

[tex]\[
(x+4)(x+1)=0
\][/tex]

A. [tex]\(x=4\)[/tex] or [tex]\(x=1\)[/tex]

B. [tex]\(x=-4\)[/tex] or [tex]\(x=1\)[/tex]

C. [tex]\(x=-4\)[/tex] or [tex]\(x=-1\)[/tex]

D. [tex]\(x=4\)[/tex] or [tex]\(x=-1\)[/tex]

Sagot :

GinnyAnswer
To solve the quadratic equation [tex]\((x+4)(x+1)=0\)[/tex], we need to find the values of [tex]\(x\)[/tex] that make this equation true.

Start by setting each factor equal to zero:

1. [tex]\(x + 4 = 0\)[/tex]
2. [tex]\(x + 1 = 0\)[/tex]

Solve each equation for [tex]\(x\)[/tex]:

1. [tex]\(x + 4 = 0\)[/tex]
[tex]\[ x = -4 \][/tex]

2. [tex]\(x + 1 = 0\)[/tex]
[tex]\[ x = -1 \][/tex]

Thus, the solutions to the equation [tex]\((x+4)(x+1)=0\)[/tex] are [tex]\(x = -4\)[/tex] and [tex]\(x = -1\)[/tex].

The correct answer is:
[tex]\[ x = -4 \text{ or } x = -1 \][/tex]
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.