Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
To determine which expression provides the same result as [tex]\(\sum_{i=0}^4\left(5 \left(\frac{1}{3}\right)^i\right)\)[/tex], we need to evaluate each given option and compare the results.
1. Option A:
[tex]\[ 5 \sum_{i=0}^1 \left(\frac{1}{3}\right)^i \][/tex]
This option involves summing the series [tex]\(\left(\frac{1}{3}\right)^i\)[/tex] for [tex]\(i = 0\)[/tex] to [tex]\(1\)[/tex], then multiplying by [tex]\(5\)[/tex]. Evaluating this:
[tex]\[ 5 \left( \left(\frac{1}{3}\right)^0 + \left(\frac{1}{3}\right)^1 \right) = 5 (1 + \frac{1}{3}) = 5 \times \frac{4}{3} = \frac{20}{3} \approx 6.67 \][/tex]
The result is approximately [tex]\(6.67\)[/tex].
2. Option B:
[tex]\[ \left(\frac{1}{3}\right) \sum_{i=0}^4 5^i \][/tex]
This option involves summing the series [tex]\(5^i\)[/tex] for [tex]\(i = 0\)[/tex] to [tex]\(4\)[/tex], then multiplying by [tex]\(\frac{1}{3}\)[/tex]. Evaluating this:
[tex]\[ \sum_{i=0}^4 5^i = 5^0 + 5^1 + 5^2 + 5^3 + 5^4 = 1 + 5 + 25 + 125 + 625 = 781 \][/tex]
Then,
[tex]\[ \left(\frac{1}{3}\right) \times 781 = \frac{781}{3} \approx 260.33 \][/tex]
The result is approximately [tex]\(260.33\)[/tex].
3. Option C:
[tex]\[ \sum_{i=0}^4 \left(5 \left(\frac{1}{3}\right)^i\right) \][/tex]
This is the original series given in the problem. Evaluating this:
[tex]\[ 5 \left(\frac{1}{3}\right)^0 + 5 \left(\frac{1}{3}\right)^1 + 5 \left(\frac{1}{3}\right)^2 + 5 \left(\frac{1}{3}\right)^3 + 5 \left(\frac{1}{3}\right)^4 \][/tex]
Simplifying each term:
[tex]\[ 5 \cdot 1 + 5 \cdot \frac{1}{3} + 5 \cdot \left(\frac{1}{3}\right)^2 + 5 \cdot \left(\frac{1}{3}\right)^3 + 5 \cdot \left(\frac{1}{3}\right)^4 \][/tex]
[tex]\[ = 5 + \frac{5}{3} + \frac{5}{9} + \frac{5}{27} + \frac{5}{81} \][/tex]
Adding these fractions:
[tex]\[ \approx 5 + 1.67 + 0.56 + 0.19 + 0.06 = 7.469 \][/tex]
The result is approximately [tex]\(7.47\)[/tex].
4. Option D:
[tex]\[ \left(\frac{1}{3}\right)^4 \sum_{i=0}^4 5 \][/tex]
This option involves summing [tex]\(\sum_{i=0}^4 5\)[/tex], then multiplying by [tex]\(\left(\frac{1}{3}\right)^4\)[/tex]. Evaluating this:
[tex]\[ \sum_{i=0}^4 5 = 5 + 5 + 5 + 5 + 5 = 25 \][/tex]
Then,
[tex]\[ \left(\frac{1}{3}\right)^4 \times 25 = \frac{1}{81} \times 25 = \frac{25}{81} \approx 0.31 \][/tex]
The result is approximately [tex]\(0.31\)[/tex].
Comparing the results:
- Option A: [tex]\(6.67\)[/tex]
- Option B: [tex]\(260.33\)[/tex]
- Option C: [tex]\(7.47\)[/tex]
- Option D: [tex]\(0.31\)[/tex]
The correct answer matches the original series' result, which is approximately [tex]\(7.47\)[/tex]. Therefore, the correct answer is:
C. [tex]\(\sum_{i=0}^4 \left(5 \left(\frac{1}{3}\right)^i\right)\)[/tex]
1. Option A:
[tex]\[ 5 \sum_{i=0}^1 \left(\frac{1}{3}\right)^i \][/tex]
This option involves summing the series [tex]\(\left(\frac{1}{3}\right)^i\)[/tex] for [tex]\(i = 0\)[/tex] to [tex]\(1\)[/tex], then multiplying by [tex]\(5\)[/tex]. Evaluating this:
[tex]\[ 5 \left( \left(\frac{1}{3}\right)^0 + \left(\frac{1}{3}\right)^1 \right) = 5 (1 + \frac{1}{3}) = 5 \times \frac{4}{3} = \frac{20}{3} \approx 6.67 \][/tex]
The result is approximately [tex]\(6.67\)[/tex].
2. Option B:
[tex]\[ \left(\frac{1}{3}\right) \sum_{i=0}^4 5^i \][/tex]
This option involves summing the series [tex]\(5^i\)[/tex] for [tex]\(i = 0\)[/tex] to [tex]\(4\)[/tex], then multiplying by [tex]\(\frac{1}{3}\)[/tex]. Evaluating this:
[tex]\[ \sum_{i=0}^4 5^i = 5^0 + 5^1 + 5^2 + 5^3 + 5^4 = 1 + 5 + 25 + 125 + 625 = 781 \][/tex]
Then,
[tex]\[ \left(\frac{1}{3}\right) \times 781 = \frac{781}{3} \approx 260.33 \][/tex]
The result is approximately [tex]\(260.33\)[/tex].
3. Option C:
[tex]\[ \sum_{i=0}^4 \left(5 \left(\frac{1}{3}\right)^i\right) \][/tex]
This is the original series given in the problem. Evaluating this:
[tex]\[ 5 \left(\frac{1}{3}\right)^0 + 5 \left(\frac{1}{3}\right)^1 + 5 \left(\frac{1}{3}\right)^2 + 5 \left(\frac{1}{3}\right)^3 + 5 \left(\frac{1}{3}\right)^4 \][/tex]
Simplifying each term:
[tex]\[ 5 \cdot 1 + 5 \cdot \frac{1}{3} + 5 \cdot \left(\frac{1}{3}\right)^2 + 5 \cdot \left(\frac{1}{3}\right)^3 + 5 \cdot \left(\frac{1}{3}\right)^4 \][/tex]
[tex]\[ = 5 + \frac{5}{3} + \frac{5}{9} + \frac{5}{27} + \frac{5}{81} \][/tex]
Adding these fractions:
[tex]\[ \approx 5 + 1.67 + 0.56 + 0.19 + 0.06 = 7.469 \][/tex]
The result is approximately [tex]\(7.47\)[/tex].
4. Option D:
[tex]\[ \left(\frac{1}{3}\right)^4 \sum_{i=0}^4 5 \][/tex]
This option involves summing [tex]\(\sum_{i=0}^4 5\)[/tex], then multiplying by [tex]\(\left(\frac{1}{3}\right)^4\)[/tex]. Evaluating this:
[tex]\[ \sum_{i=0}^4 5 = 5 + 5 + 5 + 5 + 5 = 25 \][/tex]
Then,
[tex]\[ \left(\frac{1}{3}\right)^4 \times 25 = \frac{1}{81} \times 25 = \frac{25}{81} \approx 0.31 \][/tex]
The result is approximately [tex]\(0.31\)[/tex].
Comparing the results:
- Option A: [tex]\(6.67\)[/tex]
- Option B: [tex]\(260.33\)[/tex]
- Option C: [tex]\(7.47\)[/tex]
- Option D: [tex]\(0.31\)[/tex]
The correct answer matches the original series' result, which is approximately [tex]\(7.47\)[/tex]. Therefore, the correct answer is:
C. [tex]\(\sum_{i=0}^4 \left(5 \left(\frac{1}{3}\right)^i\right)\)[/tex]
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.