Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
To determine the number of moles of KI in 125 mL of 0.20 M KI, we proceed as follows:
1. Convert the volume from milliliters to liters:
We are given 125 mL of KI solution. Since there are 1000 mL in a liter, we convert milliliters to liters:
[tex]\[ 125 \, \text{mL} = \frac{125}{1000} \, \text{L} = 0.125 \, \text{L} \][/tex]
2. Use the molarity to find the moles of KI:
Molarity (M) is defined as the number of moles of solute per liter of solution. Given that the concentration of the KI solution is 0.20 M, we can calculate the moles of KI (n) as follows:
[tex]\[ \text{Molarity} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \][/tex]
Therefore,
[tex]\[ \text{moles of KI} = \text{Molarity} \times \text{Volume in liters} \][/tex]
Substituting the known values:
[tex]\[ \text{moles of KI} = 0.20 \, \text{M} \times 0.125 \, \text{L} = 0.025 \, \text{mol} \][/tex]
Thus, the number of moles of KI present in 125 mL of 0.20 M KI is:
[tex]\[ 0.025 \, \text{mol} \][/tex]
1. Convert the volume from milliliters to liters:
We are given 125 mL of KI solution. Since there are 1000 mL in a liter, we convert milliliters to liters:
[tex]\[ 125 \, \text{mL} = \frac{125}{1000} \, \text{L} = 0.125 \, \text{L} \][/tex]
2. Use the molarity to find the moles of KI:
Molarity (M) is defined as the number of moles of solute per liter of solution. Given that the concentration of the KI solution is 0.20 M, we can calculate the moles of KI (n) as follows:
[tex]\[ \text{Molarity} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \][/tex]
Therefore,
[tex]\[ \text{moles of KI} = \text{Molarity} \times \text{Volume in liters} \][/tex]
Substituting the known values:
[tex]\[ \text{moles of KI} = 0.20 \, \text{M} \times 0.125 \, \text{L} = 0.025 \, \text{mol} \][/tex]
Thus, the number of moles of KI present in 125 mL of 0.20 M KI is:
[tex]\[ 0.025 \, \text{mol} \][/tex]
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.