Certainly! Let's start by calculating the number of moles of [tex]\( K_2CrO_4 \)[/tex] present in 100 mL of a 0.40 M [tex]\( K_2CrO_4 \)[/tex] solution.
1. Understanding the given values:
- Volume of [tex]\( K_2CrO_4 \)[/tex] solution: [tex]\( 100 \)[/tex] mL
- Concentration of [tex]\( K_2CrO_4 \)[/tex] solution: [tex]\( 0.40 \)[/tex] M
2. Convert the volume from milliliters to liters:
[tex]\( 100 \)[/tex] mL = [tex]\( 0.100 \)[/tex] L
3. Apply the formula to find moles from volume and concentration:
The formula to calculate the number of moles is:
[tex]\[
\text{moles} = \text{volume (L)} \times \text{concentration (M)}
\][/tex]
Substituting the given values:
[tex]\[
\text{moles of } K_2CrO_4 = 0.100 \, \text{L} \times 0.40 \, \text{M}
\][/tex]
4. Calculate the number of moles:
[tex]\[
\text{moles of } K_2CrO_4 = 0.100 \times 0.40 = 0.040 \, \text{moles}
\][/tex]
Therefore, the number of moles of [tex]\( K_2CrO_4 \)[/tex] present in 100 mL of a 0.40 M [tex]\( K_2CrO_4 \)[/tex] solution is [tex]\( 0.040 \)[/tex] moles.
