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Divide.

[tex]\[
\begin{array}{c}
\left(x^2+9x-20\right) \div (x-2) \\
x + [?] + \frac{}{x-2}
\end{array}
\][/tex]

Sagot :

To perform the polynomial division of [tex]\((x^2 + 9x - 20)\)[/tex] by [tex]\((x - 2)\)[/tex], we will follow the polynomial long division method step-by-step.

1. Set up the division:
[tex]\[ \frac{x^2 + 9x - 20}{x - 2} \][/tex]

2. Divide the leading term of the dividend by the leading term of the divisor:
[tex]\[ \frac{x^2}{x} = x \][/tex]
This gives us the first term of the quotient: [tex]\(x\)[/tex].

3. Multiply the entire divisor by this term [tex]\(x\)[/tex] and subtract from the dividend:
[tex]\[ (x - 2) \cdot x = x^2 - 2x \][/tex]
[tex]\[ (x^2 + 9x - 20) - (x^2 - 2x) = 11x - 20 \][/tex]

4. Repeat the process with the new polynomial [tex]\(11x - 20\)[/tex]:
[tex]\[ \frac{11x}{x} = 11 \][/tex]
This gives us the next term of the quotient: [tex]\(11\)[/tex].

5. Multiply the entire divisor by this term [tex]\(11\)[/tex] and subtract from the new polynomial:
[tex]\[ (x - 2) \cdot 11 = 11x - 22 \][/tex]
[tex]\[ (11x - 20) - (11x - 22) = 2 \][/tex]

6. Conclusion: Since [tex]\(2\)[/tex] is of lower degree than the divisor [tex]\((x - 2)\)[/tex], this is the remainder.

Thus, the quotient is [tex]\(x + 11\)[/tex] and the remainder is [tex]\(2\)[/tex]. So we can write:
[tex]\[ \frac{x^2 + 9x - 20}{x - 2} = x + 11 + \frac{2}{x - 2} \][/tex]

Therefore, the division [tex]\( (x^2 + 9x - 20) \div (x - 2) \)[/tex] results in:
[tex]\[ x + 11 + \frac{2}{x-2} \][/tex]

Hence, the complete polynomial division gives:
[tex]\[ x + 11 + \frac{2}{x-2} \][/tex]