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Final answer:
When iron is placed in copper(II) sulphate solution, a displacement reaction occurs where iron displaces copper to form iron(II) sulphate and solid copper.
Explanation:
When iron is placed in solutions of copper(II) sulphate, a displacement reaction occurs. The more reactive metal, iron, displaces the less reactive metal, copper, from the copper(II) sulphate solution, leading to the formation of iron(II) sulphate and copper metal.
The chemical equation for this reaction can be represented as:
Fe + CuSO4 -> FeSO4 + Cu
During this reaction, the iron atoms lose electrons to form Fe2+ ions, while the Cu2+ ions gain electrons to form solid copper.
Learn more about Displacement reaction here:
https://brainly.com/question/41223865
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