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What is the sum of the measures of the interior angles of a decagon?

A. [tex]$1440^{\circ}$[/tex]
B. [tex]$36^{\circ}$[/tex]
C. [tex]$2880^{\circ}$[/tex]
D. [tex]$360^{\circ}$[/tex]
E. [tex]$3600^{\circ}$[/tex]
F. [tex]$1800^{\circ}$[/tex]


Sagot :

To determine the sum of the measures of the interior angles of a decagon, we use the formula that applies to any convex polygon:

[tex]\[ \text{Sum of interior angles} = (n - 2) \times 180^\circ \][/tex]

where:
- [tex]\( n \)[/tex] is the number of sides of the polygon.

A decagon has 10 sides.

1. Substitute [tex]\( n = 10 \)[/tex] into the formula:

[tex]\[ \text{Sum of interior angles} = (10 - 2) \times 180^\circ \][/tex]

2. Simplify the expression:

[tex]\[ \text{Sum of interior angles} = 8 \times 180^\circ \][/tex]

3. Calculate the product:

[tex]\[ \text{Sum of interior angles} = 1440^\circ \][/tex]

Therefore, the sum of the measures of the interior angles of a decagon is [tex]\( 1440^\circ \)[/tex].

The correct answer is:
A. [tex]\( 1440^\circ \)[/tex]