Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Type the correct answer in each box. Use numerals instead of words.

Consider this quadratic equation.
[tex]\[ x^2 + 2x + 7 = 21 \][/tex]

The number of positive solutions to this equation is [tex]$\square$[/tex].

The approximate value of the greatest solution to the equation, rounded to the nearest hundredth, is [tex]$\square$[/tex].


Sagot :

To solve the quadratic equation [tex]\( x^2 + 2x + 7 = 21 \)[/tex], we need to follow these steps:

1. Rearrange the equation to standard form: The given equation is [tex]\( x^2 + 2x + 7 = 21 \)[/tex]. To bring it to the standard form [tex]\( ax^2 + bx + c = 0 \)[/tex], subtract 21 from both sides:
[tex]\[ x^2 + 2x + 7 - 21 = 0 \][/tex]
Simplifying, we get:
[tex]\[ x^2 + 2x - 14 = 0 \][/tex]

2. Identify the coefficients: From the standard form [tex]\( ax^2 + bx + c = 0 \)[/tex], we have:
[tex]\[ a = 1, \quad b = 2, \quad c = -14 \][/tex]

3. Calculate the discriminant: The discriminant [tex]\(\Delta\)[/tex] of the quadratic equation [tex]\( ax^2 + bx + c = 0 \)[/tex] is given by:
[tex]\[ \Delta = b^2 - 4ac \][/tex]
Plugging in the coefficients, we get:
[tex]\[ \Delta = 2^2 - 4 \cdot 1 \cdot (-14) = 4 + 56 = 60 \][/tex]

4. Determine the solutions: The quadratic formula for the roots [tex]\( x \)[/tex] of the equation [tex]\( ax^2 + bx + c = 0 \)[/tex] is given by:
[tex]\[ x = \frac{-b \pm \sqrt{\Delta}}{2a} \][/tex]
Substituting the given values:
[tex]\[ x = \frac{-2 \pm \sqrt{60}}{2 \cdot 1} \][/tex]
Simplifying further:
[tex]\[ x = \frac{-2 \pm \sqrt{60}}{2} \][/tex]
[tex]\[ x = \frac{-2 \pm \sqrt{60}}{2} \][/tex]

Solving, we get two roots [tex]\( x_1 \)[/tex] and [tex]\( x_2 \)[/tex]:
[tex]\[ x_1 = \frac{-2 + \sqrt{60}}{2}, \quad x_2 = \frac{-2 - \sqrt{60}}{2} \][/tex]

5. Determine the number of positive solutions:
[tex]\[ \sqrt{60} \approx 7.75 \][/tex]
For [tex]\( x_1 \)[/tex]:
[tex]\[ x_1 = \frac{-2 + 7.75}{2} \approx \frac{5.75}{2} \approx 2.87 \][/tex]
For [tex]\( x_2 \)[/tex]:
[tex]\[ x_2 = \frac{-2 - 7.75}{2} \approx \frac{-9.75}{2} \approx -4.87 \][/tex]

Since [tex]\( x_1 \)[/tex] is positive and [tex]\( x_2 \)[/tex] is negative, there is only 1 positive solution.

6. Round the greatest solution to the nearest hundredth: The greatest solution is [tex]\( x_1 \)[/tex], which is approximately 2.87.

So, the number of positive solutions is [tex]\( \boxed{1} \)[/tex], and the approximate value of the greatest solution, rounded to the nearest hundredth, is [tex]\( \boxed{2.87} \)[/tex].