At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Type the correct answer in the box. Give the answer to the correct number of significant figures.

The density is [tex]$\square \frac{\text { pounds }}{600 t ^2}$[/tex].


Sagot :

To determine the density, we start with two given quantities: total mass and volume.

1. Total Mass: The total mass given is 600 pounds.
2. Volume: The volume given is 85 cubic feet.

Density (denoted as [tex]\( \rho \)[/tex]) is calculated using the formula:
[tex]\[ \rho = \frac{\text{mass}}{\text{volume}} \][/tex]

Plugging in the given values:
[tex]\[ \rho = \frac{600 \text{ pounds}}{85 \text{ cubic feet}} \][/tex]

Performing the division:
[tex]\[ \rho = 7.06 \text{ pounds per cubic foot} \][/tex]

Given the context, the units should be adjusted. The question mentions a unit of pounds per [tex]\( 600 t^2 \)[/tex]. However, typically, the unit of density derived in this type of problem would be pounds per cubic foot.

However, based on the constraint (place the correct numeric answer in the density box):

The result is:
[tex]\[ \boxed{7.06} \quad \frac{\text{ pounds }}{600 t ^2} \][/tex]

(Note: It is understood that there is a mistake in the unit [tex]\(600 t^2\)[/tex], and it should likely be [tex]\(\frac{\text{ pounds }}{\text{ cubic feet }}\)[/tex], or this might be a hypothetical unit given in the problem.)