Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
To determine how much water is needed to dissolve 11 grams of calcium carbonate, we'll follow these steps:
1. Convert grams to milligrams:
- 1 gram is equal to 1000 milligrams.
- Therefore, 11 grams is equal to [tex]\( 11 \times 1000 = 11000 \)[/tex] milligrams of calcium carbonate.
2. Use the solubility information:
- The solubility of calcium carbonate is [tex]\( 14 \frac{\text { milligrams }}{\text { liter }} \)[/tex]. This means that 14 milligrams of calcium carbonate can dissolve in 1 liter of water.
- To find out how much water is required to dissolve 11000 milligrams of calcium carbonate, we can set up a proportion:
[tex]\[ \frac{14 \ \text{mg}}{1 \ \text{L}} = \frac{11000 \ \text{mg}}{x \ \text{L}} \][/tex]
3. Solve for the amount of water (x):
- Cross-multiply to solve for [tex]\( x \)[/tex]:
[tex]\[ 14 \cdot x = 11000 \][/tex]
- Divide both sides by 14 to isolate [tex]\( x \)[/tex]:
[tex]\[ x = \frac{11000}{14} = 785.7142857142857 \][/tex]
4. Express the answer to the correct number of significant figures:
- Since the given values have two significant figures (14 and 11), the answer should also be expressed with two significant figures:
[tex]\[ x \approx 790 \ \text{liters} \][/tex]
Therefore, it would take [tex]\( \mathbf{790} \text{ liters} \)[/tex] of water to fully dissolve 11 grams of calcium carbonate.
1. Convert grams to milligrams:
- 1 gram is equal to 1000 milligrams.
- Therefore, 11 grams is equal to [tex]\( 11 \times 1000 = 11000 \)[/tex] milligrams of calcium carbonate.
2. Use the solubility information:
- The solubility of calcium carbonate is [tex]\( 14 \frac{\text { milligrams }}{\text { liter }} \)[/tex]. This means that 14 milligrams of calcium carbonate can dissolve in 1 liter of water.
- To find out how much water is required to dissolve 11000 milligrams of calcium carbonate, we can set up a proportion:
[tex]\[ \frac{14 \ \text{mg}}{1 \ \text{L}} = \frac{11000 \ \text{mg}}{x \ \text{L}} \][/tex]
3. Solve for the amount of water (x):
- Cross-multiply to solve for [tex]\( x \)[/tex]:
[tex]\[ 14 \cdot x = 11000 \][/tex]
- Divide both sides by 14 to isolate [tex]\( x \)[/tex]:
[tex]\[ x = \frac{11000}{14} = 785.7142857142857 \][/tex]
4. Express the answer to the correct number of significant figures:
- Since the given values have two significant figures (14 and 11), the answer should also be expressed with two significant figures:
[tex]\[ x \approx 790 \ \text{liters} \][/tex]
Therefore, it would take [tex]\( \mathbf{790} \text{ liters} \)[/tex] of water to fully dissolve 11 grams of calcium carbonate.
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.