Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
To find the equation whose roots are numerically equal but opposite in sign of the roots of [tex]\(2 x^2 + 3 x + 4 = 0\)[/tex], let's follow these detailed steps:
### Step 1: Find the roots of the original equation
The given quadratic equation is:
[tex]\[2 x^2 + 3 x + 4 = 0\][/tex]
Using the quadratic formula [tex]\(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)[/tex], where [tex]\(a = 2\)[/tex], [tex]\(b = 3\)[/tex], and [tex]\(c = 4\)[/tex]:
1. Calculate the discriminant:
[tex]\[ \Delta = b^2 - 4ac = 3^2 - 4 \cdot 2 \cdot 4 = 9 - 32 = -23 \][/tex]
Since the discriminant is negative, the equation has two complex roots.
2. Find the roots:
[tex]\[ x = \frac{-3 \pm \sqrt{-23}}{2 \cdot 2} = \frac{-3 \pm \sqrt{23}i}{4} \][/tex]
Thus, the roots of the equation [tex]\(2 x^2 + 3 x + 4 = 0\)[/tex] are:
[tex]\[ x_1 = \frac{-3 - \sqrt{23}i}{4}, \quad x_2 = \frac{-3 + \sqrt{23}i}{4} \][/tex]
### Step 2: Determine the roots of the new equation
The roots of the new equation need to be numerically equal but opposite in sign to the roots of the original equation. Therefore, the new roots are:
[tex]\[ x_1' = \frac{3 + \sqrt{23}i}{4}, \quad x_2' = \frac{3 - \sqrt{23}i}{4} \][/tex]
### Step 3: Form the new equation
To form a quadratic equation given its roots [tex]\(x_1'\)[/tex] and [tex]\(x_2'\)[/tex], we use the fact that if [tex]\(r_1\)[/tex] and [tex]\(r_2\)[/tex] are the roots, the quadratic equation can be written as:
[tex]\[x^2 - (r_1 + r_2)x + r_1 r_2 = 0\][/tex]
For the new roots [tex]\(x_1' = \frac{3 + \sqrt{23}i}{4}\)[/tex] and [tex]\(x_2' = \frac{3 - \sqrt{23}i}{4}\)[/tex]:
1. Sum of the roots [tex]\((x_1' + x_2')\)[/tex]:
[tex]\[ \frac{3 + \sqrt{23}i}{4} + \frac{3 - \sqrt{23}i}{4} = \frac{3 + 3}{4} = \frac{6}{4} = \frac{3}{2} \][/tex]
2. Product of the roots [tex]\((x_1' \cdot x_2')\)[/tex]:
[tex]\[ \left(\frac{3 + \sqrt{23}i}{4}\right) \left(\frac{3 - \sqrt{23}i}{4}\right) = \frac{(3 + \sqrt{23}i)(3 - \sqrt{23}i)}{16} = \frac{9 - 23i^2}{16} = \frac{9 - (-23)}{16} = \frac{9 + 23}{16} = \frac{32}{16} = 2 \][/tex]
### Step 4: Write the new quadratic equation
Using the sum and product of the roots, the new quadratic equation is:
[tex]\[ x^2 - \left(\frac{3}{2}\right)x + 2 = 0 \][/tex]
Therefore, the equation whose roots are numerically equal but opposite in sign of the roots of [tex]\(2 x^2 + 3 x + 4 = 0\)[/tex] is:
[tex]\[ x^2 - \frac{3}{2} x + 2 = 0 \][/tex]
### Step 1: Find the roots of the original equation
The given quadratic equation is:
[tex]\[2 x^2 + 3 x + 4 = 0\][/tex]
Using the quadratic formula [tex]\(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)[/tex], where [tex]\(a = 2\)[/tex], [tex]\(b = 3\)[/tex], and [tex]\(c = 4\)[/tex]:
1. Calculate the discriminant:
[tex]\[ \Delta = b^2 - 4ac = 3^2 - 4 \cdot 2 \cdot 4 = 9 - 32 = -23 \][/tex]
Since the discriminant is negative, the equation has two complex roots.
2. Find the roots:
[tex]\[ x = \frac{-3 \pm \sqrt{-23}}{2 \cdot 2} = \frac{-3 \pm \sqrt{23}i}{4} \][/tex]
Thus, the roots of the equation [tex]\(2 x^2 + 3 x + 4 = 0\)[/tex] are:
[tex]\[ x_1 = \frac{-3 - \sqrt{23}i}{4}, \quad x_2 = \frac{-3 + \sqrt{23}i}{4} \][/tex]
### Step 2: Determine the roots of the new equation
The roots of the new equation need to be numerically equal but opposite in sign to the roots of the original equation. Therefore, the new roots are:
[tex]\[ x_1' = \frac{3 + \sqrt{23}i}{4}, \quad x_2' = \frac{3 - \sqrt{23}i}{4} \][/tex]
### Step 3: Form the new equation
To form a quadratic equation given its roots [tex]\(x_1'\)[/tex] and [tex]\(x_2'\)[/tex], we use the fact that if [tex]\(r_1\)[/tex] and [tex]\(r_2\)[/tex] are the roots, the quadratic equation can be written as:
[tex]\[x^2 - (r_1 + r_2)x + r_1 r_2 = 0\][/tex]
For the new roots [tex]\(x_1' = \frac{3 + \sqrt{23}i}{4}\)[/tex] and [tex]\(x_2' = \frac{3 - \sqrt{23}i}{4}\)[/tex]:
1. Sum of the roots [tex]\((x_1' + x_2')\)[/tex]:
[tex]\[ \frac{3 + \sqrt{23}i}{4} + \frac{3 - \sqrt{23}i}{4} = \frac{3 + 3}{4} = \frac{6}{4} = \frac{3}{2} \][/tex]
2. Product of the roots [tex]\((x_1' \cdot x_2')\)[/tex]:
[tex]\[ \left(\frac{3 + \sqrt{23}i}{4}\right) \left(\frac{3 - \sqrt{23}i}{4}\right) = \frac{(3 + \sqrt{23}i)(3 - \sqrt{23}i)}{16} = \frac{9 - 23i^2}{16} = \frac{9 - (-23)}{16} = \frac{9 + 23}{16} = \frac{32}{16} = 2 \][/tex]
### Step 4: Write the new quadratic equation
Using the sum and product of the roots, the new quadratic equation is:
[tex]\[ x^2 - \left(\frac{3}{2}\right)x + 2 = 0 \][/tex]
Therefore, the equation whose roots are numerically equal but opposite in sign of the roots of [tex]\(2 x^2 + 3 x + 4 = 0\)[/tex] is:
[tex]\[ x^2 - \frac{3}{2} x + 2 = 0 \][/tex]
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.
