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Sagot :
To determine the slope of the linear function [tex]\( f(x) = 5x - 2 \)[/tex], we need to identify the coefficient of the variable [tex]\( x \)[/tex].
In general, a linear function can be expressed in the form [tex]\( f(x) = mx + b \)[/tex], where:
- [tex]\( m \)[/tex] is the slope of the function,
- [tex]\( b \)[/tex] is the y-intercept, which is the point where the line crosses the y-axis.
Given the function [tex]\( f(x) = 5x - 2 \)[/tex]:
- By comparing it with the general form [tex]\( f(x) = mx + b \)[/tex], we can see that the coefficient of [tex]\( x \)[/tex] (which is [tex]\( m \)[/tex]) is 5.
Therefore, the slope of the function [tex]\( f(x) = 5x - 2 \)[/tex] is:
[tex]\[ \boxed{5} \][/tex]
In general, a linear function can be expressed in the form [tex]\( f(x) = mx + b \)[/tex], where:
- [tex]\( m \)[/tex] is the slope of the function,
- [tex]\( b \)[/tex] is the y-intercept, which is the point where the line crosses the y-axis.
Given the function [tex]\( f(x) = 5x - 2 \)[/tex]:
- By comparing it with the general form [tex]\( f(x) = mx + b \)[/tex], we can see that the coefficient of [tex]\( x \)[/tex] (which is [tex]\( m \)[/tex]) is 5.
Therefore, the slope of the function [tex]\( f(x) = 5x - 2 \)[/tex] is:
[tex]\[ \boxed{5} \][/tex]
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