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Sagot :
To find the slope of the function [tex]\( g(x) \)[/tex] given the table of values:
[tex]\[ \begin{array}{|c|c|c|c|c|c|} \hline x & 0 & 1 & 2 & 3 & 4 \\ \hline g(x) & -3 & -1 & 1 & 3 & 5 \\ \hline \end{array} \][/tex]
we can use the slope formula for a linear function, which is given by:
[tex]\[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
1. First, select any two points from the table. Let's choose the points [tex]\( (0, -3) \)[/tex] and [tex]\( (1, -1) \)[/tex].
2. Assign the coordinates:
- [tex]\( (x_1, y_1) = (0, -3) \)[/tex]
- [tex]\( (x_2, y_2) = (1, -1) \)[/tex]
3. Apply these points to the slope formula:
[tex]\[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
4. Substitute the values into the formula:
[tex]\[ \text{slope} = \frac{-1 - (-3)}{1 - 0} \][/tex]
5. Simplify the numerator:
[tex]\[ -1 - (-3) = -1 + 3 = 2 \][/tex]
6. Simplify the fraction:
[tex]\[ \text{slope} = \frac{2}{1} = 2.0 \][/tex]
Therefore, the slope of the function [tex]\( g \)[/tex] is:
[tex]\[ \boxed{2.0} \][/tex]
[tex]\[ \begin{array}{|c|c|c|c|c|c|} \hline x & 0 & 1 & 2 & 3 & 4 \\ \hline g(x) & -3 & -1 & 1 & 3 & 5 \\ \hline \end{array} \][/tex]
we can use the slope formula for a linear function, which is given by:
[tex]\[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
1. First, select any two points from the table. Let's choose the points [tex]\( (0, -3) \)[/tex] and [tex]\( (1, -1) \)[/tex].
2. Assign the coordinates:
- [tex]\( (x_1, y_1) = (0, -3) \)[/tex]
- [tex]\( (x_2, y_2) = (1, -1) \)[/tex]
3. Apply these points to the slope formula:
[tex]\[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
4. Substitute the values into the formula:
[tex]\[ \text{slope} = \frac{-1 - (-3)}{1 - 0} \][/tex]
5. Simplify the numerator:
[tex]\[ -1 - (-3) = -1 + 3 = 2 \][/tex]
6. Simplify the fraction:
[tex]\[ \text{slope} = \frac{2}{1} = 2.0 \][/tex]
Therefore, the slope of the function [tex]\( g \)[/tex] is:
[tex]\[ \boxed{2.0} \][/tex]
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