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What is the domain of [tex]$y=\sqrt{x+7}+5$[/tex]?

A. [tex]$x \geq 0$[/tex]

B. [tex][tex]$x \geq 7$[/tex][/tex]

C. [tex]$x \geq -7$[/tex]

D. all real numbers


Sagot :

To determine the domain of the function [tex]\( y = \sqrt{x + 7} + 5 \)[/tex], we need to identify the set of all possible values for [tex]\( x \)[/tex] that make the function well-defined.

The function involves a square root, [tex]\(\sqrt{x + 7}\)[/tex]. For the square root function to be defined, its radicand (the expression inside the square root) must be non-negative. Therefore, we need:
[tex]\[ x + 7 \geq 0 \][/tex]

Solving this inequality for [tex]\( x \)[/tex], we subtract 7 from both sides:
[tex]\[ x \geq -7 \][/tex]

This means that [tex]\( x \)[/tex] must be greater than or equal to [tex]\(-7\)[/tex] for the expression [tex]\(\sqrt{x + 7}\)[/tex] to be defined. Once we have this condition, the entire function [tex]\( y = \sqrt{x + 7} + 5 \)[/tex] will be defined as long as [tex]\( x \geq -7 \)[/tex].

Thus, the domain of the function [tex]\( y = \sqrt{x + 7} + 5 \)[/tex] is:
[tex]\[ x \geq -7 \][/tex]

Therefore, the correct answer is:
[tex]\[ x \geq -7 \][/tex]