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What is the range of [tex]y = \sqrt{x+7} + 5[/tex]?

A. [tex]y \geq -5[/tex]
B. [tex]y \geq 5[/tex]
C. [tex]y \geq -7[/tex]
D. All real numbers


Sagot :

To determine the range of the function [tex]\( y = \sqrt{x+7} + 5 \)[/tex], we need to analyze the behavior of the function.

1. Identify Domain Constraints:

The square root function, [tex]\(\sqrt{x}\)[/tex], is only defined for non-negative values. This implies that for [tex]\(\sqrt{x+7}\)[/tex] to be defined, the expression inside the square root must be non-negative:

[tex]\[ x + 7 \geq 0 \][/tex]

Solving for [tex]\( x \)[/tex], we get:

[tex]\[ x \geq -7 \][/tex]

2. Determine the Minimum Value of [tex]\(y\)[/tex]:

Since [tex]\( x \geq -7 \)[/tex]:

When [tex]\( x = -7 \)[/tex]:
[tex]\[ y = \sqrt{-7 + 7} + 5 = \sqrt{0} + 5 = 0 + 5 = 5 \][/tex]

3. Behavior of the Function for [tex]\( x > -7 \)[/tex]:

As [tex]\( x \)[/tex] becomes larger than [tex]\(-7\)[/tex], the value of [tex]\( x + 7 \)[/tex] increases:

[tex]\[ \sqrt{x+7} \text{ becomes larger and positive} \][/tex]

Hence, [tex]\( y \)[/tex] increases as well:

[tex]\[ y = \sqrt{x+7} + 5 \][/tex]

4. Conclusion on Range:

The minimum value of [tex]\( y \)[/tex] is [tex]\( 5 \)[/tex] when [tex]\( x = -7 \)[/tex]. As [tex]\( x \)[/tex] increases, [tex]\( y \)[/tex] also increases without an upper bound.

Therefore, the range of [tex]\( y \)[/tex] is:

[tex]\[ y \geq 5 \][/tex]

So the correct answer from the given choices is:

[tex]\[ \boxed{y \geq 5} \][/tex]
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