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Laxmi's father is 40 years old. He is 4 years older than three times Laxmi's age. (Take Laxmi's age as [tex]$n$[/tex] years.)

Sagot :

Sure! Let's solve this step by step.

1. Understand the problem statement:
- Laxmi's father is 40 years old.
- Laxmi's father is 4 years older than three times Laxmi's age.

2. Set up the relationship between Laxmi's age and her father's age:
- Let's denote Laxmi's age by [tex]\( n \)[/tex].
- According to the problem, three times Laxmi's age plus 4 years equals her father's age. This can be expressed in the form of an equation:
[tex]\[ \text{father's age} = 3n + 4 \][/tex]

3. Substitute the known value into the equation:
- We know Laxmi's father is 40 years old. Therefore, the equation becomes:
[tex]\[ 40 = 3n + 4 \][/tex]

4. Solve the equation for [tex]\( n \)[/tex]:
- First, isolate the term containing [tex]\( n \)[/tex] on one side of the equation by subtracting 4 from both sides:
[tex]\[ 40 - 4 = 3n \][/tex]
Simplifying this, we get:
[tex]\[ 36 = 3n \][/tex]

- Next, solve for [tex]\( n \)[/tex] by dividing both sides by 3:
[tex]\[ n = \frac{36}{3} \][/tex]
Simplifying this, we get:
[tex]\[ n = 12 \][/tex]

5. Conclude the result:
- Laxmi is 12 years old.

So, Laxmi's age is 12 years.