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The cost, [tex]C[/tex], to produce [tex]b[/tex] baseball bats per day is modeled by the function [tex]C(b)=0.06 b^2-7.2 b+390[/tex]. What number of bats should be produced to keep costs at a minimum?

A. 27 bats
B. 60 bats
C. 174 bats
D. 390 bats


Sagot :

To determine the number of baseball bats that should be produced to minimize the cost, we need to analyze the given cost function. The cost function provided is:

[tex]\[ C(b) = 0.06b^2 - 7.2b + 390 \][/tex]

This is a quadratic function of the form [tex]\( C(b) = ab^2 + bb + c \)[/tex], where:

- [tex]\( a = 0.06 \)[/tex]
- [tex]\( b = -7.2 \)[/tex]
- [tex]\( c = 390 \)[/tex]

For a quadratic function in the form [tex]\( ax^2 + bx + c \)[/tex], the vertex (which represents the minimum point in this case, since [tex]\( a > 0 \)[/tex]) can be found using the vertex formula:

[tex]\[ b = -\frac{B}{2A} \][/tex]

Here, [tex]\( A \)[/tex] and [tex]\( B \)[/tex] correspond to the coefficients [tex]\( a \)[/tex] and [tex]\( b \)[/tex] from the quadratic function. Plugging in our values:

- [tex]\( A = 0.06 \)[/tex]
- [tex]\( B = -7.2 \)[/tex]

The number of baseball bats [tex]\( b \)[/tex] that minimizes the cost is:

[tex]\[ b = -\frac{-7.2}{2 \cdot 0.06} \][/tex]

Simplify the expression:

[tex]\[ b = \frac{7.2}{2 \cdot 0.06} \][/tex]

[tex]\[ b = \frac{7.2}{0.12} \][/tex]

[tex]\[ b = 60 \][/tex]

Therefore, the number of baseball bats that should be produced to minimize the cost is:

[tex]\[ \boxed{60} \][/tex]

So, the correct answer is [tex]\( 60 \)[/tex] bats.