Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Type the correct answer in the box. Use numerals instead of words.

Tony bought a new car at a cost of [tex]$\$[/tex] 20,000[tex]$. The value of the car decreases by approximately $[/tex]12 \%[tex]$ each year.
Formulate the equation that gives the value, $[/tex]A(x)[tex]$, of the car $[/tex]x$ years since Tony bought the car.

[tex]\[ A(x) = 20000 \times (1 - 0.12)^x \][/tex]

Sagot :

Certainly! Let's go through the problem step by step.

1. Initial Cost of the Car:
Tony bought a car for $20,000. This is the initial value of the car.

2. Annual Decrease Rate:
The value of the car decreases by 12% each year.

3. Understanding the Rate of Decrease:
A 12% decrease can be expressed as multiplying the current value of the car by (1 - 0.12).
Mathematically:
[tex]\[ 1 - 0.12 = 0.88 \][/tex]
Therefore, each year the car retains 88% of its value from the previous year.

4. Formulating the Decrease:
To find the value of the car after [tex]\( x \)[/tex] years, we need to multiply the initial value by 0.88 raised to the power of [tex]\( x \)[/tex].

5. General Formula:
The value [tex]\( A(x) \)[/tex] of the car after [tex]\( x \)[/tex] years can be described by the exponential decay formula:
[tex]\[ A(x) = 20000 \times (0.88)^x \][/tex]

So, the equation that gives the value of the car [tex]\( x \)[/tex] years since Tony bought it is:
[tex]\[ A(x) = 20000 \times (0.88)^x \][/tex]

This is your desired final expression.
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.