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The height of an arch is modeled by the equation [tex]y = -x^2 - 6x + 16[/tex]. Which of the following gives the width of the arch at its base?

A. The [tex]$y$[/tex]-coordinate of the vertex
B. Double the [tex]$x$[/tex]-coordinate of the vertex
C. The [tex]$y$[/tex]-intercept of the equation
D. The difference between the zeroes


Sagot :

To determine the width of the arch at its base, we need to identify the points where the arch intersects the [tex]\( x \)[/tex]-axis, also known as the x-intercepts or the zeroes of the equation.

The given equation for the height of the arch is:
[tex]\[ y = -x^2 - 6x + 16 \][/tex]

To find the x-intercepts, we set [tex]\( y \)[/tex] equal to zero and solve for [tex]\( x \)[/tex]:
[tex]\[ -x^2 - 6x + 16 = 0 \][/tex]

Solving this quadratic equation for [tex]\( x \)[/tex] will give us the zeroes. By factoring or using the quadratic formula, we find the roots:
[tex]\[ x = -8 \][/tex]
and
[tex]\[ x = 2 \][/tex]

These are the points where the arch meets the x-axis. To find the width of the arch at its base, we calculate the distance between these two x-intercepts.

The distance (or width of the arch) is given by the absolute difference between these x-values:
[tex]\[ \text{Width of the arch} = |2 - (-8)| = |2 + 8| = 10 \][/tex]

Thus, the width of the arch at its base is 10 units. This corresponds to "the difference between the zeroes."

Therefore, the correct option is:
- the difference between the zeroes
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