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Which choice is equivalent to the product below when [tex]$x\ \textgreater \ 0$[/tex]?

[tex] \sqrt{\frac{3x}{2}} \cdot \sqrt{\frac{x}{6}} [/tex]

A. [tex] \frac{\sqrt{x}}{2} [/tex]
B. [tex] \frac{x}{2} [/tex]
C. [tex] \frac{x}{4} [/tex]
D. [tex] \frac{\sqrt{3x}}{4} [/tex]


Sagot :

To find the equivalent expression for the product [tex]\(\sqrt{\frac{3x}{2}} \cdot \sqrt{\frac{x}{6}}\)[/tex], we will simplify the expression step-by-step.

First, we use the property of square roots that states:
[tex]\[ \sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b} \][/tex]

Applying this property to the given expression:
[tex]\[ \sqrt{\frac{3x}{2}} \cdot \sqrt{\frac{x}{6}} = \sqrt{\left( \frac{3x}{2} \right) \cdot \left( \frac{x}{6} \right)} \][/tex]

Next, we multiply the fractions inside the square root:
[tex]\[ \left( \frac{3x}{2} \right) \cdot \left( \frac{x}{6} \right) = \frac{3x \cdot x}{2 \cdot 6} = \frac{3x^2}{12} \][/tex]

We can simplify the fraction:
[tex]\[ \frac{3x^2}{12} = \frac{x^2}{4} \][/tex]

Now, we take the square root of the simplified fraction:
[tex]\[ \sqrt{\frac{x^2}{4}} = \frac{\sqrt{x^2}}{\sqrt{4}} = \frac{x}{2} \][/tex]

Thus, the equivalent expression for [tex]\(\sqrt{\frac{3x}{2}} \cdot \sqrt{\frac{x}{6}}\)[/tex] is:
[tex]\[ \frac{x}{2} \][/tex]

So, the correct choice is:
[tex]\[ \boxed{\text{B}} \][/tex]