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The image of a point is given by the rule [tex]r_{y=-x}(x, y) \rightarrow(-4,9)[/tex]. What are the coordinates of its pre-image?

A. [tex](-9, 4)[/tex]
B. [tex](-4, -9)[/tex]
C. [tex](4, 9)[/tex]
D. [tex](9, -4)[/tex]


Sagot :

To determine the coordinates of the pre-image given the transformation rule [tex]\( r_{y=-x}(x, y) \rightarrow (-4, 9) \)[/tex], let's analyze how this transformation works.

The transformation [tex]\( r_{y=-x} \)[/tex] reflects a point [tex]\((x, y)\)[/tex] over the line [tex]\( y = -x \)[/tex]. When a point [tex]\((x, y)\)[/tex] is reflected over this line, the coordinates change according to the following rule:
[tex]\[ (x, y) \rightarrow (-y, -x) \][/tex]

We are given that the image of a point under this transformation is [tex]\( (-4, 9) \)[/tex]. Therefore, we need to find the original coordinates [tex]\((x, y)\)[/tex] such that:
[tex]\[ (-y, -x) = (-4, 9) \][/tex]

From this equation, we can set up the following system of equations:
[tex]\[ -y = -4 \][/tex]
[tex]\[ -x = 9 \][/tex]

Solving these, we get:
[tex]\[ y = 4 \][/tex]
[tex]\[ x = -9 \][/tex]

Therefore, the coordinates of the pre-image are:
[tex]\[ (-9, 4) \][/tex]

Thus, the correct answer is:
[tex]\[ \boxed{(-9, 4)} \][/tex]