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Sagot :
Sure, let's solve the equation [tex]\( S = BC - 6 \)[/tex] for the variable [tex]\( B \)[/tex].
1. Start with the given equation:
[tex]\[ S = BC - 6 \][/tex]
2. Our goal is to solve for [tex]\( B \)[/tex]. First, we need to isolate the term involving [tex]\( B \)[/tex]. To do this, add 6 to both sides of the equation:
[tex]\[ S + 6 = BC - 6 + 6 \][/tex]
3. Simplifying the right-hand side, we get:
[tex]\[ S + 6 = BC \][/tex]
4. Now we need [tex]\( B \)[/tex] by itself on one side of the equation. To achieve this, divide both sides of the equation by [tex]\( C \)[/tex]:
[tex]\[ \frac{S + 6}{C} = \frac{BC}{C} \][/tex]
5. Simplify the right-hand side:
[tex]\[ \frac{S + 6}{C} = B \][/tex]
Therefore, the solution for [tex]\( B \)[/tex] is:
[tex]\[ B = \frac{S + 6}{C} \][/tex]
1. Start with the given equation:
[tex]\[ S = BC - 6 \][/tex]
2. Our goal is to solve for [tex]\( B \)[/tex]. First, we need to isolate the term involving [tex]\( B \)[/tex]. To do this, add 6 to both sides of the equation:
[tex]\[ S + 6 = BC - 6 + 6 \][/tex]
3. Simplifying the right-hand side, we get:
[tex]\[ S + 6 = BC \][/tex]
4. Now we need [tex]\( B \)[/tex] by itself on one side of the equation. To achieve this, divide both sides of the equation by [tex]\( C \)[/tex]:
[tex]\[ \frac{S + 6}{C} = \frac{BC}{C} \][/tex]
5. Simplify the right-hand side:
[tex]\[ \frac{S + 6}{C} = B \][/tex]
Therefore, the solution for [tex]\( B \)[/tex] is:
[tex]\[ B = \frac{S + 6}{C} \][/tex]
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