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1. Simplify [tex]$(2x - 2y)(2y + 8) =$[/tex] ?

A. [tex]$4xy + 16x - 4y^2 - 16y$[/tex]
B. [tex][tex]$4xy - 4y^2$[/tex][/tex]
C. [tex]$4xy - 16x - 4y^2 - 16y$[/tex]

Sagot :

GinnyAnswer
Sure! Let's simplify the expression [tex]\((2x - 2y)(2y + 8)\)[/tex] step-by-step.

1. Write Down the Expression:
[tex]\[ (2x - 2y)(2y + 8) \][/tex]

2. Distribute Each Term in the First Parentheses to Each Term in the Second Parentheses:
To do this, use the distributive property (also known as the FOIL method for binomials):

[tex]\[ = 2x \cdot 2y + 2x \cdot 8 - 2y \cdot 2y - 2y \cdot 8 \][/tex]

3. Perform the Multiplications:
[tex]\[ = 4xy + 16x - 4y^2 - 16y \][/tex]

4. Combine Like Terms (if any):
In this case, there are no like terms to combine.

Therefore, the simplified expression is:
[tex]\[ 4xy + 16x - 4y^2 - 16y \][/tex]

Now, let's compare this with the provided options:

A. [tex]\(4xy + 16x - 4y^2 - 16y\)[/tex]

B. [tex]\(4xy - 4y^2\)[/tex]

C. [tex]\(4xy - 16x - 4y^2 - 16y\)[/tex]

The correct answer is:
A. [tex]\(4xy + 16x - 4y^2 - 16y\)[/tex]
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