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Sagot :
To determine which of the given values is not a possible value for a probability, we need to recall the range of valid probabilities. A probability must be a number between 0 and 1, inclusive. That means a valid probability `p` must satisfy [tex]\(0 \leq p \leq 1\)[/tex].
Let's examine each option to see whether it falls within this range:
- Option A: 0.82
- 0.82 is within the range [0, 1]. Therefore, 0.82 is a valid probability.
- Option B: 1.001
- 1.001 is greater than 1. Probabilities cannot exceed 1. Therefore, 1.001 is not a valid probability.
- Option C: [tex]\(\frac{10}{100}\)[/tex]
- [tex]\(\frac{10}{100} = 0.1\)[/tex]
- 0.1 is within the range [0, 1]. Therefore, [tex]\(\frac{10}{100}\)[/tex] is a valid probability.
- Option D: [tex]\(\frac{1}{16}\)[/tex]
- [tex]\(\frac{1}{16} \approx 0.0625\)[/tex]
- 0.0625 is within the range [0, 1]. Therefore, [tex]\(\frac{1}{16}\)[/tex] is a valid probability.
After examining all the options, we can conclude that the value which is not a possible value for a probability is:
B. 1.001
Let's examine each option to see whether it falls within this range:
- Option A: 0.82
- 0.82 is within the range [0, 1]. Therefore, 0.82 is a valid probability.
- Option B: 1.001
- 1.001 is greater than 1. Probabilities cannot exceed 1. Therefore, 1.001 is not a valid probability.
- Option C: [tex]\(\frac{10}{100}\)[/tex]
- [tex]\(\frac{10}{100} = 0.1\)[/tex]
- 0.1 is within the range [0, 1]. Therefore, [tex]\(\frac{10}{100}\)[/tex] is a valid probability.
- Option D: [tex]\(\frac{1}{16}\)[/tex]
- [tex]\(\frac{1}{16} \approx 0.0625\)[/tex]
- 0.0625 is within the range [0, 1]. Therefore, [tex]\(\frac{1}{16}\)[/tex] is a valid probability.
After examining all the options, we can conclude that the value which is not a possible value for a probability is:
B. 1.001
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