Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
To find [tex]\(\theta\)[/tex] when [tex]\(0^\circ < \theta < 360^\circ\)[/tex] and [tex]\(\sin \theta = -\frac{\sqrt{3}}{2}\)[/tex] with [tex]\(\theta\)[/tex] in the fourth quadrant (QIV), follow these steps:
1. Determine the reference angle:
- The reference angle is the angle in the first quadrant that has the same sine value ignoring the sign. For [tex]\(\sin \theta = \frac{\sqrt{3}}{2}\)[/tex], the reference angle is [tex]\(60^\circ\)[/tex].
2. Place the angle in the correct quadrant:
- Since we know [tex]\(\sin \theta = -\frac{\sqrt{3}}{2}\)[/tex], and sine is negative in the fourth quadrant, we will use the reference angle to find [tex]\(\theta\)[/tex] in QIV.
3. Calculate the angle in the fourth quadrant:
- In the fourth quadrant, the angle can be found using [tex]\(360^\circ\)[/tex] minus the reference angle.
- Thus, [tex]\(\theta = 360^\circ - 60^\circ\)[/tex].
- So, [tex]\(\theta = 300^\circ\)[/tex].
Therefore, [tex]\(\theta = 300^\circ\)[/tex] and the reference angle is [tex]\(60^\circ\)[/tex].
1. Determine the reference angle:
- The reference angle is the angle in the first quadrant that has the same sine value ignoring the sign. For [tex]\(\sin \theta = \frac{\sqrt{3}}{2}\)[/tex], the reference angle is [tex]\(60^\circ\)[/tex].
2. Place the angle in the correct quadrant:
- Since we know [tex]\(\sin \theta = -\frac{\sqrt{3}}{2}\)[/tex], and sine is negative in the fourth quadrant, we will use the reference angle to find [tex]\(\theta\)[/tex] in QIV.
3. Calculate the angle in the fourth quadrant:
- In the fourth quadrant, the angle can be found using [tex]\(360^\circ\)[/tex] minus the reference angle.
- Thus, [tex]\(\theta = 360^\circ - 60^\circ\)[/tex].
- So, [tex]\(\theta = 300^\circ\)[/tex].
Therefore, [tex]\(\theta = 300^\circ\)[/tex] and the reference angle is [tex]\(60^\circ\)[/tex].
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.