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Sumy is working in geometry class and is given figure [tex]\( ABCD \)[/tex] in the coordinate plane to reflect. The coordinates of point [tex]\( D \)[/tex] are [tex]\((a, b)\)[/tex] and she reflects the figure over the line [tex]\( y = x \)[/tex]. What are the coordinates of the image [tex]\( D' \)[/tex]?

A. [tex]\((a, -b)\)[/tex]
B. [tex]\((b, a)\)[/tex]
C. [tex]\((-a, b)\)[/tex]
D. [tex]\((-b, -a)\)[/tex]


Sagot :

To solve Sumy's problem of reflecting point [tex]\( D \)[/tex] with coordinates [tex]\( (a, b) \)[/tex] over the line [tex]\( y = x \)[/tex], we need to understand the geometric transformation properties of reflections.

Reflecting a point over the line [tex]\( y = x \)[/tex] swaps its [tex]\( x \)[/tex] and [tex]\( y \)[/tex] coordinates. Here's a detailed step-by-step explanation:

1. Identify the original coordinates of [tex]\( D \)[/tex]:
[tex]\[ D = (a, b) \][/tex]

2. Reflect the point over the line [tex]\( y = x \)[/tex]:
- When reflecting over the line [tex]\( y = x \)[/tex], the [tex]\( x \)[/tex]-coordinate becomes the [tex]\( y \)[/tex]-coordinate, and the [tex]\( y \)[/tex]-coordinate becomes the [tex]\( x \)[/tex]-coordinate.
- This means the new coordinates, [tex]\( D' \)[/tex], are given by:
[tex]\[ D' = (b, a) \][/tex]

Thus, after reflecting the point [tex]\( D \)[/tex] over the line [tex]\( y = x \)[/tex], the coordinates of [tex]\( D' \)[/tex] are:

[tex]\[ (b, a) \][/tex]

Therefore, the correct answer is:

[tex]\[ \boxed{(b, a)} \][/tex]