atticus30
Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Consider the reaction below.

[tex]\[ H_2PO_4^{-} + H_2O \rightarrow H_3O^{+} + HPO_4^{2-} \][/tex]

Which of the following is a base-conjugate acid pair?

A. [tex]\( H_2O \)[/tex] and [tex]\( H_3O^{+} \)[/tex]
B. [tex]\( H_2O \)[/tex] and [tex]\( H_2PO_4^{-} \)[/tex]
C. [tex]\( H_2PO_4^{-} \)[/tex] and [tex]\( HPO_4^{2-} \)[/tex]
D. [tex]\( H_2PO_4^{-} \)[/tex] and [tex]\( H_3O^{+} \)[/tex]

Sagot :

GinnyAnswer
The concept of conjugate acid-base pairs is fundamental in acid-base chemistry. When an acid donates a proton (H⁺), it forms its conjugate base, and when a base accepts a proton (H⁺), it forms its conjugate acid. Let's analyze the given reaction step by step in the context of conjugate acid-base pairs:

[tex]\[ H_2PO_4^{-} + H_2O \rightarrow H_3O^+ + HPO_4^{2-} \][/tex]

1. Identify the species involved in the reaction:
- [tex]\(H_2PO_4^{-}\)[/tex]
- [tex]\(H_2O\)[/tex]
- [tex]\(H_3O^+\)[/tex]
- [tex]\(HPO_4^{2-}\)[/tex]

2. Determine which substances act as acids and bases:
- [tex]\(H_2PO_4^{-}\)[/tex] donates a proton (acts as an acid) and becomes [tex]\(HPO_4^{2-}\)[/tex].
- [tex]\(H_2O\)[/tex] accepts a proton (acts as a base) and becomes [tex]\(H_3O^+\)[/tex].

3. Match the acids with their corresponding conjugate bases:
- [tex]\(H_2PO_4^{-}\)[/tex] (acid) loses a proton to become [tex]\(HPO_4^{2-}\)[/tex] (conjugate base).
- [tex]\(H_2O\)[/tex] (base) gains a proton to become [tex]\(H_3O^+\)[/tex] (conjugate acid).

Using above information, we can identify the base-conjugate acid pairs:

- [tex]\(H_2O\)[/tex] and [tex]\(H_3O^+\)[/tex] form a conjugate acid-base pair.
- [tex]\(H_2PO_4^{-}\)[/tex] and [tex]\(HPO_4^{2-}\)[/tex] form another conjugate acid-base pair.

Thus, the correct answer to the given question is:

[tex]\(H_2PO_4^{-}\)[/tex] and [tex]\(HPO_4^{2-}\)[/tex].
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.