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Question #6: Mario wants to install a wooden deck around a rectangular swimming pool. The function [tex]C(w) = 120w^2 + 1800w[/tex] models the cost, where the cost, [tex]C(w)[/tex], is in dollars and the width, [tex]w[/tex], is in meters. How wide will the deck be if he has [tex]\$4080[/tex] to spend?

Sagot :

To determine the width of the deck Mario can install around his swimming pool given that he has [tex]$4080 to spend, we follow these steps: 1. Identify the cost function provided: The cost function given is \( C(w) = 120w^2 + 1800w \), where \( C(w) \) is the cost in dollars and \( w \) is the width in meters. 2. Set the given total cost equal to the cost function: Since Mario has $[/tex]4080 to spend, we equate the cost function to this amount:
[tex]\[ 120w^2 + 1800w = 4080 \][/tex]

3. Formulate the quadratic equation:
Rearrange the equation to standard form:
[tex]\[ 120w^2 + 1800w - 4080 = 0 \][/tex]

4. Simplify the quadratic equation:
We can simplify this equation by dividing every term by 60 to make it easier to solve:
[tex]\[ 2w^2 + 30w - 68 = 0 \][/tex]

5. Solve the simplified quadratic equation using the quadratic formula:
The quadratic formula is given by:
[tex]\[ w = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \][/tex]
For our equation [tex]\(2w^2 + 30w - 68 = 0\)[/tex], the coefficients are:
[tex]\[ a = 2, \quad b = 30, \quad c = -68 \][/tex]

Plug these values into the quadratic formula:
[tex]\[ w = \frac{-30 \pm \sqrt{30^2 - 4 \cdot 2 \cdot (-68)}}{2 \cdot 2} \][/tex]
[tex]\[ w = \frac{-30 \pm \sqrt{900 + 544}}{4} \][/tex]
[tex]\[ w = \frac{-30 \pm \sqrt{1444}}{4} \][/tex]
[tex]\[ w = \frac{-30 \pm 38}{4} \][/tex]

6. Calculate the roots:
Solve for the two possible values of [tex]\( w \)[/tex]:
[tex]\[ w_1 = \frac{-30 + 38}{4} = \frac{8}{4} = 2 \][/tex]
[tex]\[ w_2 = \frac{-30 - 38}{4} = \frac{-68}{4} = -17 \][/tex]

7. Select the valid solution:
Since a width cannot be negative, the valid solution is:
[tex]\[ w = 2 \][/tex]

Thus, the width of the deck that Mario can install around his swimming pool, given he has \$4080 to spend, is 2 meters.
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