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Drag each number to the correct location on the equation. Each number can be used more than once, but not all numbers will be used. Balance the equation with the correct coefficients.

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[tex]\[ \text{___} KClO_3 \rightarrow \text{___} KCl + \text{___} O_2 \][/tex]

Sagot :

GinnyAnswer
To balance the chemical equation [tex]\( KClO_3 \rightarrow KCl + O_2 \)[/tex], we need to determine the correct coefficients that ensure the same number of each type of atom on both sides of the reaction.

Let's follow these steps to balance the equation:

1. Identify the elements involved:
- Potassium (K)
- Chlorine (Cl)
- Oxygen (O)

2. Write the unbalanced equation:
[tex]\[ KClO_3 \rightarrow KCl + O_2 \][/tex]

3. Balance the potassium (K) and chlorine (Cl) atoms:
- There is 1 K on the left side and 1 K on the right side.
- There is 1 Cl on the left side and 1 Cl on the right side.
- Therefore, initially, no extra coefficients are needed for K and Cl at this stage. However, we will adjust this after balancing oxygen.

4. Balance the oxygen (O) atoms:
- On the left side, there are 3 oxygen atoms in [tex]\( KClO_3 \)[/tex].
- On the right side, oxygen is in [tex]\( O_2 \)[/tex], which means it appears in pairs. We need to find a coefficient that gives a total count of oxygen atoms that matches the left side.

5. To balance oxygen, we can put a coefficient of 2 in front of [tex]\( KClO_3 \)[/tex], which gives us:
[tex]\[ 2 KClO_3 \rightarrow KCl + O_2 \][/tex]

6. Adjust the left side and check if it affects other atoms:
- Now, we have 2 K and 2 Cl on the left side because of the coefficient 2 in front of [tex]\( KClO_3 \)[/tex].

To balance the K and Cl atoms:
- We should put a coefficient of 2 in front of [tex]\( KCl \)[/tex], making sure we have 2 K and 2 Cl on the right side:
[tex]\[ 2 KClO_3 \rightarrow 2 KCl + O_2 \][/tex]

7. Now let’s balance the oxygen atoms by determining the coefficient for [tex]\( O_2 \)[/tex]:
- On the left side, we have [tex]\( 2 \times 3 = 6 \)[/tex] oxygen atoms (from [tex]\( 2 KClO_3 \)[/tex]).
- On the right side, we currently have 2 oxygen atoms.
- To balance this, we need a coefficient of 3 in front of [tex]\( O_2 \)[/tex] because [tex]\( 3 \times 2 = 6 \)[/tex].

Hence, the fully balanced equation with the correct coefficients is:
[tex]\[ 2 KClO_3 \rightarrow 2 KCl + 3 O_2 \][/tex]

So, the balanced equation is:
[tex]\[ 2 KClO_3 \rightarrow 2 KCl + 3 O_2 \][/tex]
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