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Sure! Let's find the exact value for [tex]\( \cos \left(2 \sin^{-1} \frac{7}{10}\right) \)[/tex] step by step.
First, recognize that [tex]\( \sin^{-1} \frac{7}{10} \)[/tex] represents an angle [tex]\(\theta\)[/tex] such that [tex]\( \sin(\theta) = \frac{7}{10} \)[/tex].
### Step 1: Determine [tex]\( \sin(\theta) \)[/tex]
Given:
[tex]\[ \sin(\theta) = \frac{7}{10} \][/tex]
### Step 2: Calculate [tex]\( \cos(\theta) \)[/tex] using the Pythagorean identity
We know from the Pythagorean identity:
[tex]\[ \sin^2(\theta) + \cos^2(\theta) = 1 \][/tex]
Thus,
[tex]\[ \cos^2(\theta) = 1 - \sin^2(\theta) \][/tex]
Substitute the value of [tex]\( \sin(\theta) = \frac{7}{10} \)[/tex]:
[tex]\[ \cos^2(\theta) = 1 - \left(\frac{7}{10}\right)^2 \][/tex]
[tex]\[ \cos^2(\theta) = 1 - \frac{49}{100} \][/tex]
[tex]\[ \cos^2(\theta) = \frac{100}{100} - \frac{49}{100} \][/tex]
[tex]\[ \cos^2(\theta) = \frac{51}{100} \][/tex]
[tex]\[ \cos(\theta) = \sqrt{\frac{51}{100}} = \sqrt{\frac{51}}{10} \][/tex]
To match the given numerical result, we recognize that:
[tex]\[ \cos(\theta) \approx 0.7141 \][/tex]
### Step 3: Use the double-angle formula for cosine
The double-angle formula for cosine is:
[tex]\[ \cos(2\theta) = 2 \cos^2(\theta) - 1 \][/tex]
### Step 4: Substitute the value of [tex]\( \cos(\theta) \)[/tex] into the double-angle formula
[tex]\[ \cos(2\theta) = 2 \left(\sqrt{\frac{51}}{10}\right)^2 - 1 \][/tex]
Simplify:
[tex]\[ \cos(2\theta) = 2 \left(\frac{51}{100}\right) - 1 \][/tex]
[tex]\[ \cos(2\theta) = 2 \times 0.51 - 1 \][/tex]
[tex]\[ \cos(2\theta) = 1.02 - 1 \][/tex]
[tex]\[ \cos(2\theta) \approx 0.02 \][/tex]
So the exact value of [tex]\( \cos \left(2 \sin^{-1} \frac{7}{10}\right) \)[/tex] is:
[tex]\[ \boxed{0.02} \][/tex]
First, recognize that [tex]\( \sin^{-1} \frac{7}{10} \)[/tex] represents an angle [tex]\(\theta\)[/tex] such that [tex]\( \sin(\theta) = \frac{7}{10} \)[/tex].
### Step 1: Determine [tex]\( \sin(\theta) \)[/tex]
Given:
[tex]\[ \sin(\theta) = \frac{7}{10} \][/tex]
### Step 2: Calculate [tex]\( \cos(\theta) \)[/tex] using the Pythagorean identity
We know from the Pythagorean identity:
[tex]\[ \sin^2(\theta) + \cos^2(\theta) = 1 \][/tex]
Thus,
[tex]\[ \cos^2(\theta) = 1 - \sin^2(\theta) \][/tex]
Substitute the value of [tex]\( \sin(\theta) = \frac{7}{10} \)[/tex]:
[tex]\[ \cos^2(\theta) = 1 - \left(\frac{7}{10}\right)^2 \][/tex]
[tex]\[ \cos^2(\theta) = 1 - \frac{49}{100} \][/tex]
[tex]\[ \cos^2(\theta) = \frac{100}{100} - \frac{49}{100} \][/tex]
[tex]\[ \cos^2(\theta) = \frac{51}{100} \][/tex]
[tex]\[ \cos(\theta) = \sqrt{\frac{51}{100}} = \sqrt{\frac{51}}{10} \][/tex]
To match the given numerical result, we recognize that:
[tex]\[ \cos(\theta) \approx 0.7141 \][/tex]
### Step 3: Use the double-angle formula for cosine
The double-angle formula for cosine is:
[tex]\[ \cos(2\theta) = 2 \cos^2(\theta) - 1 \][/tex]
### Step 4: Substitute the value of [tex]\( \cos(\theta) \)[/tex] into the double-angle formula
[tex]\[ \cos(2\theta) = 2 \left(\sqrt{\frac{51}}{10}\right)^2 - 1 \][/tex]
Simplify:
[tex]\[ \cos(2\theta) = 2 \left(\frac{51}{100}\right) - 1 \][/tex]
[tex]\[ \cos(2\theta) = 2 \times 0.51 - 1 \][/tex]
[tex]\[ \cos(2\theta) = 1.02 - 1 \][/tex]
[tex]\[ \cos(2\theta) \approx 0.02 \][/tex]
So the exact value of [tex]\( \cos \left(2 \sin^{-1} \frac{7}{10}\right) \)[/tex] is:
[tex]\[ \boxed{0.02} \][/tex]
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