Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Let's consider the function [tex]\( y = 3 \cot \left( \frac{1}{2} x \right) - 4 \)[/tex]. We need to determine where this function has vertical asymptotes. A vertical asymptote occurs where the argument of the cotangent function is undefined.
The cotangent function, [tex]\( \cot(\theta) \)[/tex], is undefined where [tex]\( \theta = n\pi \)[/tex], where [tex]\( n \)[/tex] is any integer.
We are dealing with [tex]\( \cot \left( \frac{1}{2} x \right) \)[/tex]. Therefore, we need to find [tex]\( x \)[/tex] such that:
[tex]\[ \frac{1}{2} x = n\pi \][/tex]
Solving for [tex]\( x \)[/tex] gives:
[tex]\[ x = 2n\pi \][/tex]
This tells us that the function will have vertical asymptotes at [tex]\( x = 2n\pi \)[/tex] for [tex]\( n \)[/tex] being any integer.
Let's check each given option:
A. [tex]\( x = \pm 2\pi \)[/tex]:
- For [tex]\( n = 1 \)[/tex], [tex]\( x = 2(1)\pi = 2\pi \)[/tex]
- For [tex]\( n = -1 \)[/tex], [tex]\( x = 2(-1)\pi = -2\pi \)[/tex]
Thus, both [tex]\( x = 2\pi \)[/tex] and [tex]\( x = -2\pi \)[/tex] fit the form [tex]\( x = 2n\pi \)[/tex]. Hence, [tex]\( x = \pm 2\pi \)[/tex] are vertical asymptotes. This option is correct.
B. [tex]\( x = \frac{\pi}{2} \)[/tex]:
- If we set [tex]\( \frac{1}{2} x = \frac{\pi}{2} \)[/tex], solving for [tex]\( x \)[/tex] would give [tex]\( x = \pi \)[/tex], which does not fit the form [tex]\( 2n\pi \)[/tex].
Thus, this option is incorrect.
C. [tex]\( x = 3\pi \)[/tex]:
- If we set [tex]\( x = 3\pi \)[/tex], dividing both sides by [tex]\( 2 \)[/tex] gives [tex]\( \frac{1}{2} x = \frac{3\pi}{2} \)[/tex], which is not an integer multiple of [tex]\( \pi \)[/tex].
Thus, [tex]\( x = 3\pi \)[/tex] does not fit the form [tex]\( 2n\pi \)[/tex] and this option is incorrect.
D. [tex]\( x = 0 \)[/tex]:
- For [tex]\( n = 0 \)[/tex], [tex]\( x = 2(0)\pi = 0 \)[/tex].
Thus, [tex]\( x = 0 \)[/tex] fits the form [tex]\( 2n\pi \)[/tex]. Hence, this option is correct.
Combining the valid choices, the correct answers are:
A. [tex]\( x = \pm 2\pi \)[/tex]
D. [tex]\( x = 0 \)[/tex]
So, the vertical asymptotes of the function are given by the options A and D.
The cotangent function, [tex]\( \cot(\theta) \)[/tex], is undefined where [tex]\( \theta = n\pi \)[/tex], where [tex]\( n \)[/tex] is any integer.
We are dealing with [tex]\( \cot \left( \frac{1}{2} x \right) \)[/tex]. Therefore, we need to find [tex]\( x \)[/tex] such that:
[tex]\[ \frac{1}{2} x = n\pi \][/tex]
Solving for [tex]\( x \)[/tex] gives:
[tex]\[ x = 2n\pi \][/tex]
This tells us that the function will have vertical asymptotes at [tex]\( x = 2n\pi \)[/tex] for [tex]\( n \)[/tex] being any integer.
Let's check each given option:
A. [tex]\( x = \pm 2\pi \)[/tex]:
- For [tex]\( n = 1 \)[/tex], [tex]\( x = 2(1)\pi = 2\pi \)[/tex]
- For [tex]\( n = -1 \)[/tex], [tex]\( x = 2(-1)\pi = -2\pi \)[/tex]
Thus, both [tex]\( x = 2\pi \)[/tex] and [tex]\( x = -2\pi \)[/tex] fit the form [tex]\( x = 2n\pi \)[/tex]. Hence, [tex]\( x = \pm 2\pi \)[/tex] are vertical asymptotes. This option is correct.
B. [tex]\( x = \frac{\pi}{2} \)[/tex]:
- If we set [tex]\( \frac{1}{2} x = \frac{\pi}{2} \)[/tex], solving for [tex]\( x \)[/tex] would give [tex]\( x = \pi \)[/tex], which does not fit the form [tex]\( 2n\pi \)[/tex].
Thus, this option is incorrect.
C. [tex]\( x = 3\pi \)[/tex]:
- If we set [tex]\( x = 3\pi \)[/tex], dividing both sides by [tex]\( 2 \)[/tex] gives [tex]\( \frac{1}{2} x = \frac{3\pi}{2} \)[/tex], which is not an integer multiple of [tex]\( \pi \)[/tex].
Thus, [tex]\( x = 3\pi \)[/tex] does not fit the form [tex]\( 2n\pi \)[/tex] and this option is incorrect.
D. [tex]\( x = 0 \)[/tex]:
- For [tex]\( n = 0 \)[/tex], [tex]\( x = 2(0)\pi = 0 \)[/tex].
Thus, [tex]\( x = 0 \)[/tex] fits the form [tex]\( 2n\pi \)[/tex]. Hence, this option is correct.
Combining the valid choices, the correct answers are:
A. [tex]\( x = \pm 2\pi \)[/tex]
D. [tex]\( x = 0 \)[/tex]
So, the vertical asymptotes of the function are given by the options A and D.
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.