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Barton conducts an experiment using three metallic bars that might be magnets. The bars are labeled [tex]$A$[/tex], [tex]$B$[/tex], and [tex]$C$[/tex]. The ends of each bar are numbered 1 or 2.

He places the end of one bar close to an end of a second bar and records his results in the table shown.

\begin{tabular}{|c|c|c|}
\hline
End & End & Result \\
\hline
A1 & B1 & Attract \\
\hline
A2 & C1 & Repel \\
\hline
B2 & A1 & Attract \\
\hline
\end{tabular}

Based on the data, which prediction should he expect to occur?

A. A2 repels B1.
B. C2 attracts B2.
C. B1 repels C1.
D. A1 attracts C2.

Sagot :

GinnyAnswer
To find out which predictions Barton should expect to occur based on the experiment data, let's analyze each given result step-by-step.

1. Initial Observations:
- A1 attracted to B1: This means A1 and B1 have opposite polarities, since opposite poles attract.
- A2 repelled by C1: This means A2 and C1 have the same polarity, since like poles repel.
- B2 attracted to A1: This means B2 and A1 have opposite polarities, same as B1 and A1 because B2 attracts A1, they must be on the same side of the pole consideration.

2. Polarity Inferences:
- From A1 attracted to B1, we know A1 and B1 are opposite in polarity.
- From B2 attracted to A1, B2 must be the same polarity as B1.
- From A2 repelled by C1, A2 and C1 are the same polarity.

3. Detailed Polarity Assignments:
- If A1 and B1 have opposite polarities:
- Let's say, hypothetically, A1 is North and B1 is South.
- Consequently, B2 (which attracts A1) must also be South (same polarity as B1).
- Hence, A2 which is at the same bar as A1, would be South (opposite side of bar A compared to North A1) since a magnet’s opposite poles have alternate positioning.
- Since A2 repels C1, both A2 and C1 must both be South.

4. Predicting Interactions:
- A2 repels B1:
- Both are South, thus same polarity repels.
- C2 attracts B2:
- Since B2 is South and C1 is South and both poles repel, then C2 must be North therefore attract to B2.
- B1 repels C1:
- Both being South, they are same polarity and thus repel.
- A1 attracts C2:
- A1 is North and if C2 is North, there should be no attraction. Therefore, C2 must be South like rotation of C1 and they will attract the North A1.

Based on the outcome analysis:

- A2 repels B1 (Since both are South) - True
- C2 attracts B2 (C2 is North and B2 is South) - True
- B1 repels C1 (Both being South end) - True
- A1 attracts C2 (Different polarities A1(North) and C2(South)) - True

Thus, the predictions Barton should expect to occur are:
[tex]\[ (True, 1), (True, 1), (True, 1), (True, 1) \][/tex]

These conclusions follow logically from the observed interactions and the principles of magnetic attraction and repulsion.
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