Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
To determine the theoretical yield of aspirin, follow these steps:
1. Determine the moles of salicylic acid:
Use the molar mass of salicylic acid [tex]\(C_7H_6O_3\)[/tex] and the given mass to calculate the number of moles.
[tex]\[ \text{Molar mass of salicylic acid} = 138.12 \, \text{g/mol} \][/tex]
[tex]\[ \text{Mass of salicylic acid} = 3.04 \, \text{g} \][/tex]
The number of moles of salicylic acid can be calculated using the formula:
[tex]\[ \text{Moles of salicylic acid} = \frac{\text{Mass of salicylic acid}}{\text{Molar mass of salicylic acid}} \][/tex]
[tex]\[ \text{Moles of salicylic acid} = \frac{3.04 \, \text{g}}{138.12 \, \text{g/mol}} = 0.022009846510280914 \, \text{mol} \][/tex]
2. Determine the moles of aspirin:
According to the balanced chemical equation, the reaction ratio of salicylic acid to aspirin is 1:1. Therefore, the number of moles of aspirin formed is equal to the number of moles of salicylic acid.
[tex]\[ \text{Moles of aspirin} = 0.022009846510280914 \, \text{mol} \][/tex]
3. Calculate the theoretical yield of aspirin:
Use the molar mass of aspirin [tex]\(C_9H_8O_4\)[/tex] and the number of moles of aspirin to find the theoretical yield in grams.
[tex]\[ \text{Molar mass of aspirin} = 180.15 \, \text{g/mol} \][/tex]
The theoretical yield of aspirin can be calculated using the formula:
[tex]\[ \text{Theoretical yield of aspirin} = \text{Moles of aspirin} \times \text{Molar mass of aspirin} \][/tex]
[tex]\[ \text{Theoretical yield of aspirin} = 0.022009846510280914 \, \text{mol} \times 180.15 \, \text{g/mol} = 3.9650738488271067 \, \text{g} \][/tex]
Thus, the theoretical yield of aspirin when reacting 3.04 g of salicylic acid with an excess of acetic anhydride is approximately 3.97 grams.
1. Determine the moles of salicylic acid:
Use the molar mass of salicylic acid [tex]\(C_7H_6O_3\)[/tex] and the given mass to calculate the number of moles.
[tex]\[ \text{Molar mass of salicylic acid} = 138.12 \, \text{g/mol} \][/tex]
[tex]\[ \text{Mass of salicylic acid} = 3.04 \, \text{g} \][/tex]
The number of moles of salicylic acid can be calculated using the formula:
[tex]\[ \text{Moles of salicylic acid} = \frac{\text{Mass of salicylic acid}}{\text{Molar mass of salicylic acid}} \][/tex]
[tex]\[ \text{Moles of salicylic acid} = \frac{3.04 \, \text{g}}{138.12 \, \text{g/mol}} = 0.022009846510280914 \, \text{mol} \][/tex]
2. Determine the moles of aspirin:
According to the balanced chemical equation, the reaction ratio of salicylic acid to aspirin is 1:1. Therefore, the number of moles of aspirin formed is equal to the number of moles of salicylic acid.
[tex]\[ \text{Moles of aspirin} = 0.022009846510280914 \, \text{mol} \][/tex]
3. Calculate the theoretical yield of aspirin:
Use the molar mass of aspirin [tex]\(C_9H_8O_4\)[/tex] and the number of moles of aspirin to find the theoretical yield in grams.
[tex]\[ \text{Molar mass of aspirin} = 180.15 \, \text{g/mol} \][/tex]
The theoretical yield of aspirin can be calculated using the formula:
[tex]\[ \text{Theoretical yield of aspirin} = \text{Moles of aspirin} \times \text{Molar mass of aspirin} \][/tex]
[tex]\[ \text{Theoretical yield of aspirin} = 0.022009846510280914 \, \text{mol} \times 180.15 \, \text{g/mol} = 3.9650738488271067 \, \text{g} \][/tex]
Thus, the theoretical yield of aspirin when reacting 3.04 g of salicylic acid with an excess of acetic anhydride is approximately 3.97 grams.
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.